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Two numbers are such that twice the greater number exceeds twice the smaller one by 18 and 1/3 of the smaller and 1/5 of the greater number are together 21. The numbers are: 
  • a)
    (36, 45)
  • b)
    (45, 36) 
  • c)
    (50, 41)
  • d)
    (55, 46)
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Two numbers are such that twice the greater number exceeds twice the s...
Let greater number is 'x'
Smaller number be 'y
Given,greater number exceeds twice the smaller i.e 2x-2y=18...........1
1/3 of smaller and 1/5 of greater i.e 1/3×y+1/5×x=21 this is convert as 3x+5y=315......2
By solving 1 and 2 we get x=45 and y=36
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Most Upvoted Answer
Two numbers are such that twice the greater number exceeds twice the s...
Given Information:
- Twice the greater number exceeds twice the smaller one by 18
- 1/3 of the smaller and 1/5 of the greater number are together 21

To find:
- The numbers

Assumption:
- Let the smaller number be x and the greater number be y

Calculation:
- According to the first statement, we can write the equation as: 2y = 2x + 18
- Simplifying the equation, we get: y = x + 9
- According to the second statement, we can write the equation as: (1/3)x + (1/5)y = 21
- Substituting the value of y from equation 1, we get: (1/3)x + (1/5)(x + 9) = 21
- Simplifying the equation, we get: 8x + 45 = 315
- Solving for x, we get: x = 30
- Substituting the value of x in equation 1, we get: y = 39

Therefore, the numbers are (30, 39), which is option B.
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Two numbers are such that twice the greater number exceeds twice the s...
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Two numbers are such that twice the greater number exceeds twice the smaller one by 18 and 1/3 of the smaller and 1/5 of the greater number are together 21. The numbers are:a)(36, 45)b)(45, 36)c)(50, 41)d)(55, 46)Correct answer is option 'B'. Can you explain this answer?
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