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If a cross is made between two individuals each having genotype Bb, two offsprings are obtained. out of these has dominant trait what is the probability that the second offspring will exhibit recessive trait
- a)1/4
- b)100
- c)Zero
- d)3/4
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
If a cross is made between two individuals each having genotype Bb, tw...
The parent's genotype is "Bb".
Parent generation : Bb x Bb
Gametes:
F1 generation = 3 dominant : 1 recessive. Hence, the probability of a child to be recessive is 1/4. Option A is the correct answer.
Parent generation : Bb x Bb
Gametes:
F1 generation = 3 dominant : 1 recessive. Hence, the probability of a child to be recessive is 1/4. Option A is the correct answer.
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If a cross is made between two individuals each having genotype Bb, tw...
Probability of Offsprings exhibiting Dominant Trait
To solve this problem, we need to understand the principles of Mendelian genetics and the concept of probability.
Mendelian Genetics
Mendelian genetics describes the inheritance of traits from parents to offspring. In this case, we are considering a cross between two individuals, each having the genotype Bb. The genotype Bb represents one dominant allele (B) and one recessive allele (b) for a particular trait.
Probability of Dominant Trait
When two individuals with the genotype Bb are crossed, there are four possible combinations of alleles in the offspring: BB, Bb, bB, and bb. Out of these four possibilities, three have the dominant allele (B) and one has the recessive allele (b).
Therefore, the probability of an offspring exhibiting the dominant trait is 3/4 or 75%.
Probability of Second Offspring exhibiting Recessive Trait
Now, let's consider the probability of the second offspring exhibiting the recessive trait, given that the first offspring has the dominant trait.
Since the parents are both heterozygous (Bb), they can each produce two types of gametes: one with the dominant allele (B) and one with the recessive allele (b). When these gametes combine during fertilization, there are four possible combinations for the second offspring: BB, Bb, bB, and bb.
Out of these four possibilities, only one has the recessive allele (b). Therefore, the probability of the second offspring exhibiting the recessive trait is 1/4 or 25%.
Hence, the correct answer is option A - 1/4.
To solve this problem, we need to understand the principles of Mendelian genetics and the concept of probability.
Mendelian Genetics
Mendelian genetics describes the inheritance of traits from parents to offspring. In this case, we are considering a cross between two individuals, each having the genotype Bb. The genotype Bb represents one dominant allele (B) and one recessive allele (b) for a particular trait.
Probability of Dominant Trait
When two individuals with the genotype Bb are crossed, there are four possible combinations of alleles in the offspring: BB, Bb, bB, and bb. Out of these four possibilities, three have the dominant allele (B) and one has the recessive allele (b).
Therefore, the probability of an offspring exhibiting the dominant trait is 3/4 or 75%.
Probability of Second Offspring exhibiting Recessive Trait
Now, let's consider the probability of the second offspring exhibiting the recessive trait, given that the first offspring has the dominant trait.
Since the parents are both heterozygous (Bb), they can each produce two types of gametes: one with the dominant allele (B) and one with the recessive allele (b). When these gametes combine during fertilization, there are four possible combinations for the second offspring: BB, Bb, bB, and bb.
Out of these four possibilities, only one has the recessive allele (b). Therefore, the probability of the second offspring exhibiting the recessive trait is 1/4 or 25%.
Hence, the correct answer is option A - 1/4.
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If a cross is made between two individuals each having genotype Bb, two offsprings are obtained. out of these has dominant trait what is the probability that the second offspring will exhibit recessive traita)1/4b)100c)Zerod)3/4Correct answer is option 'A'. Can you explain this answer?
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