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A line segment is of length 10 units. If the coordinates of its one end are (2, –3) and the abscissa of the other end is 10, then its ordinate is :
  • a)
    9, 6
  • b)
    3, -9
  • c)
    -3, 9
  • d)
    9, -6
Correct answer is option 'B'. Can you explain this answer?
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A line segment is of length 10 units. If the coordinates of its one en...
A line segment is of length 10 units. If the coordinates of its one end are (2, 4), what are the possible coordinates of its other end?

Since the length of the line segment is 10 units, we can use the distance formula to find the distance between the two end points. The distance formula is given by:

d = √((x2 - x1)^2 + (y2 - y1)^2)

where (x1, y1) are the coordinates of the first point and (x2, y2) are the coordinates of the second point.

In this case, the coordinates of the first point are (2, 4). Let's say the coordinates of the second point are (x, y). Plugging in these values into the distance formula, we get:

10 = √((x - 2)^2 + (y - 4)^2)

Squaring both sides of the equation, we get:

100 = (x - 2)^2 + (y - 4)^2

Expanding the equation, we get:

100 = x^2 - 4x + 4 + y^2 - 8y + 16

Rearranging the terms, we get:

x^2 - 4x + y^2 - 8y = 100 - 4 - 16

x^2 - 4x + y^2 - 8y = 80

Completing the square for the x and y terms, we get:

(x - 2)^2 - 4 + (y - 4)^2 - 16 = 80

(x - 2)^2 + (y - 4)^2 = 100

Now, we have the equation of a circle centered at (2, 4) with a radius of 10 units.

So, the possible coordinates of the other end of the line segment are any point on this circle.
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A line segment is of length 10 units. If the coordinates of its one en...
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A line segment is of length 10 units. If the coordinates of its one end are (2, –3) and the abscissa of the other endis 10, then its ordinate is :a)9, 6b)3, -9c)-3, 9d)9, -6Correct answer is option 'B'. Can you explain this answer?
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