Class 12 Exam > Class 12 Questions > When 1 mole of non volatile solute is dissolv...
Start Learning for Free
When 1 mole of non volatile solute is dissolved in three moles of solvent the vapour pressure of the solution relative to the vapour pressure of the pure solvent is 1/4 ,How?
Most Upvoted Answer
When 1 mole of non volatile solute is dissolved in three moles of solv...
Actually we know more fraction x(ki)=moles of solute/moles of solution
so=1/1+3 =1/4
then psolvent-psolution/psolvent =mole fraction
=1/4
hence done
so=1/1+3 =1/4
then psolvent-psolution/psolvent =mole fraction
=1/4
hence done
Community Answer
When 1 mole of non volatile solute is dissolved in three moles of solv...
Explanation:
The vapour pressure of a solution is the pressure exerted by the vapours of the solvent above the solution. When a non-volatile solute is added to the solvent, it lowers the vapour pressure of the solvent because the solute molecules occupy space at the surface of the solvent and prevent the solvent molecules from escaping into the vapour phase.
Formula:
According to Raoult's law, the vapour pressure of a solution is directly proportional to the mole fraction of the solvent in the solution.
Calculation:
Given,
Number of moles of solute = 1
Number of moles of solvent = 3
Relative vapour pressure = 1/4
Let the vapour pressure of the pure solvent be P₀.
According to Raoult's law,
Vapour pressure of the solution (P) = (mole fraction of solvent) x (vapour pressure of pure solvent)
Mole fraction of solvent = 3/4
P = (3/4)P₀
Given,
Relative vapour pressure = P/P₀ = 1/4
(3/4)P₀/P₀ = 1/4
3/4 = 1/4
This is not possible, so there must be an error in the question or the calculation.
The relative vapour pressure of a solution can never be less than 0 or greater than 1.
Therefore, we conclude that the given information is incorrect or incomplete.
The vapour pressure of a solution is the pressure exerted by the vapours of the solvent above the solution. When a non-volatile solute is added to the solvent, it lowers the vapour pressure of the solvent because the solute molecules occupy space at the surface of the solvent and prevent the solvent molecules from escaping into the vapour phase.
Formula:
According to Raoult's law, the vapour pressure of a solution is directly proportional to the mole fraction of the solvent in the solution.
Calculation:
Given,
Number of moles of solute = 1
Number of moles of solvent = 3
Relative vapour pressure = 1/4
Let the vapour pressure of the pure solvent be P₀.
According to Raoult's law,
Vapour pressure of the solution (P) = (mole fraction of solvent) x (vapour pressure of pure solvent)
Mole fraction of solvent = 3/4
P = (3/4)P₀
Given,
Relative vapour pressure = P/P₀ = 1/4
(3/4)P₀/P₀ = 1/4
3/4 = 1/4
This is not possible, so there must be an error in the question or the calculation.
The relative vapour pressure of a solution can never be less than 0 or greater than 1.
Therefore, we conclude that the given information is incorrect or incomplete.
|
Explore Courses for Class 12 exam
|
|
Similar Class 12 Doubts
When 1 mole of non volatile solute is dissolved in three moles of solvent the vapour pressure of the solution relative to the vapour pressure of the pure solvent is 1/4 ,How?
Question Description
When 1 mole of non volatile solute is dissolved in three moles of solvent the vapour pressure of the solution relative to the vapour pressure of the pure solvent is 1/4 ,How? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about When 1 mole of non volatile solute is dissolved in three moles of solvent the vapour pressure of the solution relative to the vapour pressure of the pure solvent is 1/4 ,How? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When 1 mole of non volatile solute is dissolved in three moles of solvent the vapour pressure of the solution relative to the vapour pressure of the pure solvent is 1/4 ,How?.
When 1 mole of non volatile solute is dissolved in three moles of solvent the vapour pressure of the solution relative to the vapour pressure of the pure solvent is 1/4 ,How? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about When 1 mole of non volatile solute is dissolved in three moles of solvent the vapour pressure of the solution relative to the vapour pressure of the pure solvent is 1/4 ,How? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When 1 mole of non volatile solute is dissolved in three moles of solvent the vapour pressure of the solution relative to the vapour pressure of the pure solvent is 1/4 ,How?.
Solutions for When 1 mole of non volatile solute is dissolved in three moles of solvent the vapour pressure of the solution relative to the vapour pressure of the pure solvent is 1/4 ,How? in English & in Hindi are available as part of our courses for Class 12.
Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of When 1 mole of non volatile solute is dissolved in three moles of solvent the vapour pressure of the solution relative to the vapour pressure of the pure solvent is 1/4 ,How? defined & explained in the simplest way possible. Besides giving the explanation of
When 1 mole of non volatile solute is dissolved in three moles of solvent the vapour pressure of the solution relative to the vapour pressure of the pure solvent is 1/4 ,How?, a detailed solution for When 1 mole of non volatile solute is dissolved in three moles of solvent the vapour pressure of the solution relative to the vapour pressure of the pure solvent is 1/4 ,How? has been provided alongside types of When 1 mole of non volatile solute is dissolved in three moles of solvent the vapour pressure of the solution relative to the vapour pressure of the pure solvent is 1/4 ,How? theory, EduRev gives you an
ample number of questions to practice When 1 mole of non volatile solute is dissolved in three moles of solvent the vapour pressure of the solution relative to the vapour pressure of the pure solvent is 1/4 ,How? tests, examples and also practice Class 12 tests.
|
|
Explore Courses for Class 12 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup