CA Foundation Exam > CA Foundation Questions > 51c31 is equal toa)51c20b)2.50c20c)2.45c15d)n...
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51c31 is equal to
- a)51c20
- b)2.50c20
- c)2.45c15
- d)none of these
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
51c31 is equal toa)51c20b)2.50c20c)2.45c15d)none of theseCorrect answe...
To understand this question, we need to know what "c" means in the given numbers.
In mathematics, "c" is used to represent "combination". Combination refers to the selection of objects without regard to the order of selection.
For example, if we have 5 objects A, B, C, D, E, then the number of ways to select 3 objects without regarding their order would be represented as 5c3.
Now, let's look at the given options:
a) 51c20
b) 2.50c20
c) 2.45c15
d) none of these
Since the question asks us to find the value of 51c31, we can eliminate options b and c as they do not involve the number 51.
So, the correct answer is option a, which represents 51c20.
To calculate the value of 51c20, we can use the formula for combination:
nCk = n! / (k! * (n-k)!)
where n is the total number of objects and k is the number of objects being selected.
Using this formula, we get:
51c20 = 51! / (20! * (51-20)!)
= (51 * 50 * 49 * ... * 32 * 31!) / (20 * 19 * 18 * ... * 2 * 1 * 31!)
= 3891061760
Therefore, the value of 51c31 is 3891061760.
In mathematics, "c" is used to represent "combination". Combination refers to the selection of objects without regard to the order of selection.
For example, if we have 5 objects A, B, C, D, E, then the number of ways to select 3 objects without regarding their order would be represented as 5c3.
Now, let's look at the given options:
a) 51c20
b) 2.50c20
c) 2.45c15
d) none of these
Since the question asks us to find the value of 51c31, we can eliminate options b and c as they do not involve the number 51.
So, the correct answer is option a, which represents 51c20.
To calculate the value of 51c20, we can use the formula for combination:
nCk = n! / (k! * (n-k)!)
where n is the total number of objects and k is the number of objects being selected.
Using this formula, we get:
51c20 = 51! / (20! * (51-20)!)
= (51 * 50 * 49 * ... * 32 * 31!) / (20 * 19 * 18 * ... * 2 * 1 * 31!)
= 3891061760
Therefore, the value of 51c31 is 3891061760.
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Community Answer
51c31 is equal toa)51c20b)2.50c20c)2.45c15d)none of theseCorrect answe...
We are asked to find the value of 51C31 and identify which of the given options is equivalent to it.
Step 1: Understanding the Combination Formula
The formula for combinations is given by:
Combination Formula: C(n, r) = n! / (r!(n - r)!)
Step 2: Simplifying the Combination
The given problem is C(51, 31). Using the symmetry property of combinations:
Symmetry Property: C(n, r) = C(n, n - r)
This property tells us that:
C(51, 31) = C(51, 20)
This is because 51 - 31 = 20.
Step 3: Conclusion
Therefore, 51C31 is equal to 51C20.
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51c31 is equal toa)51c20b)2.50c20c)2.45c15d)none of theseCorrect answer is option 'A'. Can you explain this answer?
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