Number of atoms is 560 g of Fe (atomic mass = 56 g mol-1)a)Is twice th...
Fe atom= 560/56 =10 mole
= 10 x NA atom
option(A) = 5 mol
5 x NA
option (B) = 20/1 = 20
20 x NA
View all questions of this test
Number of atoms is 560 g of Fe (atomic mass = 56 g mol-1)a)Is twice th...
Given:
Mass of Fe = 560 g
Atomic mass of Fe = 56 g/mol
a) Number of atoms in 560 g of Fe is twice that of 70 g N (Nitrogen)
Atomic mass of N = 14 g/mol
Number of atoms in 70 g of N = (70 g / 14 g/mol) x (6.02 x 10^23) = 3.01 x 10^24 atoms
Number of atoms in 560 g of Fe = (560 g / 56 g/mol) x (6.02 x 10^23) = 6.02 x 10^24 atoms
Therefore, the number of atoms in 560 g of Fe is twice that of 70 g N.
b) Number of atoms in 560 g of Fe is half that of 20 g H (Hydrogen)
Atomic mass of H = 1 g/mol
Number of atoms in 20 g of H = (20 g / 1 g/mol) x (6.02 x 10^23) = 1.20 x 10^25 atoms
Number of atoms in 560 g of Fe = (560 g / 56 g/mol) x (6.02 x 10^23) = 6.02 x 10^24 atoms
Therefore, the number of atoms in 560 g of Fe is not half that of 20 g H.
c) Both statements are correct
From the above calculations, we can see that the first statement is correct and the second statement is incorrect. Therefore, option C is the correct answer.
Number of atoms is 560 g of Fe (atomic mass = 56 g mol-1)a)Is twice th...
Let N be Avogadro's number.
The atomic/molar masses of Fe,N2 and H2 are 56 g/mol, 28 g/mol and 2 g/mol respectively.
560 g Fe=56g/mol560g=10 mol Fe=10N atoms.
70 g N2=28g/mol70g=2.5 moles N2=2×2.5N=5N atoms.
Twice of this corresponds to 2×5N=10N.
20 g of H2=2g/mol20g=10 mole H2=2×10N=20N atoms.
Half of this =0.5×20N=10N atoms.