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Let P be the point on the parabola y2 = 4x which is at the shortest distance from the center S of the circle x2 + y2 – 4x – 16y + 64 = 0. Let Q be the point on the circle dividing the line segment SP internally. Thena)SP = 2√5b)SQ:QP = ((√5+1):2)c)the x-intercept of the normal to the parabola at P is 6d)the slope of the tangent to the circle at Q is 1/2Correct answer is option 'A,C,D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared
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the JEE exam syllabus. Information about Let P be the point on the parabola y2 = 4x which is at the shortest distance from the center S of the circle x2 + y2 – 4x – 16y + 64 = 0. Let Q be the point on the circle dividing the line segment SP internally. Thena)SP = 2√5b)SQ:QP = ((√5+1):2)c)the x-intercept of the normal to the parabola at P is 6d)the slope of the tangent to the circle at Q is 1/2Correct answer is option 'A,C,D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for Let P be the point on the parabola y2 = 4x which is at the shortest distance from the center S of the circle x2 + y2 – 4x – 16y + 64 = 0. Let Q be the point on the circle dividing the line segment SP internally. Thena)SP = 2√5b)SQ:QP = ((√5+1):2)c)the x-intercept of the normal to the parabola at P is 6d)the slope of the tangent to the circle at Q is 1/2Correct answer is option 'A,C,D'. Can you explain this answer?.
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Here you can find the meaning of Let P be the point on the parabola y2 = 4x which is at the shortest distance from the center S of the circle x2 + y2 – 4x – 16y + 64 = 0. Let Q be the point on the circle dividing the line segment SP internally. Thena)SP = 2√5b)SQ:QP = ((√5+1):2)c)the x-intercept of the normal to the parabola at P is 6d)the slope of the tangent to the circle at Q is 1/2Correct answer is option 'A,C,D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Let P be the point on the parabola y2 = 4x which is at the shortest distance from the center S of the circle x2 + y2 – 4x – 16y + 64 = 0. Let Q be the point on the circle dividing the line segment SP internally. Thena)SP = 2√5b)SQ:QP = ((√5+1):2)c)the x-intercept of the normal to the parabola at P is 6d)the slope of the tangent to the circle at Q is 1/2Correct answer is option 'A,C,D'. Can you explain this answer?, a detailed solution for Let P be the point on the parabola y2 = 4x which is at the shortest distance from the center S of the circle x2 + y2 – 4x – 16y + 64 = 0. Let Q be the point on the circle dividing the line segment SP internally. Thena)SP = 2√5b)SQ:QP = ((√5+1):2)c)the x-intercept of the normal to the parabola at P is 6d)the slope of the tangent to the circle at Q is 1/2Correct answer is option 'A,C,D'. Can you explain this answer? has been provided alongside types of Let P be the point on the parabola y2 = 4x which is at the shortest distance from the center S of the circle x2 + y2 – 4x – 16y + 64 = 0. Let Q be the point on the circle dividing the line segment SP internally. Thena)SP = 2√5b)SQ:QP = ((√5+1):2)c)the x-intercept of the normal to the parabola at P is 6d)the slope of the tangent to the circle at Q is 1/2Correct answer is option 'A,C,D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Let P be the point on the parabola y2 = 4x which is at the shortest distance from the center S of the circle x2 + y2 – 4x – 16y + 64 = 0. Let Q be the point on the circle dividing the line segment SP internally. Thena)SP = 2√5b)SQ:QP = ((√5+1):2)c)the x-intercept of the normal to the parabola at P is 6d)the slope of the tangent to the circle at Q is 1/2Correct answer is option 'A,C,D'. Can you explain this answer? tests, examples and also practice JEE tests.