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The area of isosceles triangle is 60cm² and the length of each one of its equal sides is 13 cm. find its base.?
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The area of isosceles triangle is 60cm² and the length of each one of ...

ΔABC is isosceles
AB = AC =13cm
Let's drop a perpendicular AD from A to BC with height h
Let CD = x

Area of ΔADC = 1/2(xh)
Area of ΔABC = xh = 60
h = 60/x
In ΔADC by pythagoras theorem

Let Solving we get
u = 144 or 25
⇒ x = 12 or 5
CD = x
BC = 2x
BC could take two possible values 24 cm and 10 cm
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The area of isosceles triangle is 60cm² and the length of each one of its equal sides is 13 cm. find its base.?
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