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1, 3-Dichloropropane one reaction with Zn and NaI gives:
  • a)
    Propane
  • b)
    1-chloropropane
  • c)
    Cyclohexene
  • d)
    Cyclopropane 
Correct answer is option 'D'. Can you explain this answer?
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1, 3-Dichloropropane one reaction with Zn and NaI gives:a)Propaneb)1-c...
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1, 3-Dichloropropane one reaction with Zn and NaI gives:a)Propaneb)1-c...
Reaction of 1,3-Dichloropropane with Zn and NaI
The reaction of 1,3-dichloropropane with Zn and NaI is a dehalogenation reaction known as the Wurtz reaction. The reaction involves the formation of a carbon-carbon bond by the reaction of two alkyl halides in the presence of a reducing agent (Zn) and a dehalogenating agent (NaI). The reaction can be represented as follows:

1,3-Dichloropropane + 2NaI + 2Zn → Cyclopropane + 2NaCl + 2ZnI

Explanation of the Answer
The product of the Wurtz reaction between 1,3-dichloropropane and Zn/NaI is cyclopropane. This is because the reaction involves the formation of a cyclopropane ring by the reaction of two molecules of 1,3-dichloropropane. The zinc acts as a reducing agent, while the sodium iodide acts as a dehalogenating agent, removing the chlorine atoms from the 1,3-dichloropropane molecules. The resulting carbon-carbon bond formation leads to the formation of the cyclopropane ring.

Conclusion
In conclusion, the Wurtz reaction between 1,3-dichloropropane and Zn/NaI results in the formation of cyclopropane. This reaction is a useful method for the synthesis of cyclopropanes and is widely used in organic chemistry.
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1, 3-Dichloropropane one reaction with Zn and NaI gives:a)Propaneb)1-chloropropanec)Cyclohexened)CyclopropaneCorrect answer is option 'D'. Can you explain this answer?
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