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If a spring extends by x on loading, then the energy stored by the spring is (if T is tension in the spring and k is spring constant)
  • a)
    T2/2x
  • b)
    T2/2k
  • c)
    2k/T2
  • d)
    2 T2/k
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
If a spring extends by x on loading, then the energy stored by the spr...
As the block is being pulled the tension developed in the spring is nothing but spring force. So, T = kx .Also, the energy developed while pulling the spring is, E = (kx^2)/2On multiplying and dividing the above relation with k we get,E = (k^2x^2)/2k = (kx)^2/2kTherefore we get the relation as, E = T^2/2k
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Community Answer
If a spring extends by x on loading, then the energy stored by the spr...
Explanation:

When a spring is loaded or stretched by a certain distance, it stores potential energy within it. This potential energy is given by the formula:

Energy stored = (1/2)kx^2

Where:
- k is the spring constant (a measure of the stiffness of the spring)
- x is the distance the spring is stretched or extended

Now, let's understand why the correct answer is option 'B' - T^2/2k.

1. Relationship between tension (T) and spring constant (k):
The tension (T) in a spring is directly proportional to its spring constant (k). This relationship is given by Hooke's Law:

T = kx

Where:
- T is the tension in the spring
- k is the spring constant
- x is the distance the spring is stretched or extended

2. Substituting the value of T in the energy stored formula:
Using the relationship T = kx, we can substitute the value of T in the energy stored formula:

Energy stored = (1/2)(T^2/k)

3. Simplifying the expression:
We can simplify the expression by multiplying T^2/k with 1/2:

(1/2)(T^2/k) = T^2/2k

4. Conclusion:
Therefore, the energy stored by the spring when it extends by x on loading is T^2/2k. This means that the correct answer is option 'B'.
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