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Which of the following aqueous solution has minimum freezing point ? [1991]
- a)0.01 m NaCl
- b)0.005 m C2H5OH
- c)0.005 m MgI2
- d)0.005 m MgSO4.
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Which of the following aqueous solution has minimum freezing point ? [...
ΔTf = i × Kf × m Van't Hoff factor, i = 2 for NaCl, hence ΔTf = 0.02 Kf which is maximum in the present case.
Hence ΔTf is maximum or freezing point is minimum.
Hence ΔTf is maximum or freezing point is minimum.
Most Upvoted Answer
Which of the following aqueous solution has minimum freezing point ? [...
Explanation:
The freezing point of a solution is lowered when a solute is added to a solvent. The extent of lowering of the freezing point depends on the concentration of the solute in the solution. The van't Hoff factor (i) of the solute also plays a role in determining the extent of lowering of the freezing point.
The formula to calculate the freezing point depression is given by:
ΔTf = Kf x i x molality
where ΔTf is the change in freezing point, Kf is the cryoscopic constant of the solvent, i is the van't Hoff factor of the solute and molality is the concentration of the solute in moles per kg of solvent.
In this question, all the solutions have the same molality of 0.005 m. Therefore, the solution with the highest van't Hoff factor (i) will have the maximum freezing point depression and hence the minimum freezing point.
Let's calculate the van't Hoff factor for each of the given solutions:
a) NaCl: NaCl dissociates into Na+ and Cl- ions in water. Therefore, i = 2.
b) C2H5OH: Ethanol does not dissociate in water. Therefore, i = 1.
c) MgI2: MgI2 dissociates into Mg2+ and 2I- ions in water. Therefore, i = 3.
d) MgSO4: MgSO4 dissociates into Mg2+ and SO42- ions in water. Therefore, i = 2.
Now, let's calculate the freezing point depression for each solution using the formula mentioned above:
a) ΔTf = Kf x i x molality = Kf x 2 x 0.005 = 0.01 K
b) ΔTf = Kf x i x molality = Kf x 1 x 0.005 = 0.005 K
c) ΔTf = Kf x i x molality = Kf x 3 x 0.005 = 0.015 K
d) ΔTf = Kf x i x molality = Kf x 2 x 0.005 = 0.01 K
Since solution a) and d) have the same van't Hoff factor (i = 2) and the same molality (0.005 m), they will have the same freezing point depression. Therefore, the solution with the highest van't Hoff factor (i = 3) is solution c). Hence, the solution with the minimum freezing point is solution a) (0.01 K).
The freezing point of a solution is lowered when a solute is added to a solvent. The extent of lowering of the freezing point depends on the concentration of the solute in the solution. The van't Hoff factor (i) of the solute also plays a role in determining the extent of lowering of the freezing point.
The formula to calculate the freezing point depression is given by:
ΔTf = Kf x i x molality
where ΔTf is the change in freezing point, Kf is the cryoscopic constant of the solvent, i is the van't Hoff factor of the solute and molality is the concentration of the solute in moles per kg of solvent.
In this question, all the solutions have the same molality of 0.005 m. Therefore, the solution with the highest van't Hoff factor (i) will have the maximum freezing point depression and hence the minimum freezing point.
Let's calculate the van't Hoff factor for each of the given solutions:
a) NaCl: NaCl dissociates into Na+ and Cl- ions in water. Therefore, i = 2.
b) C2H5OH: Ethanol does not dissociate in water. Therefore, i = 1.
c) MgI2: MgI2 dissociates into Mg2+ and 2I- ions in water. Therefore, i = 3.
d) MgSO4: MgSO4 dissociates into Mg2+ and SO42- ions in water. Therefore, i = 2.
Now, let's calculate the freezing point depression for each solution using the formula mentioned above:
a) ΔTf = Kf x i x molality = Kf x 2 x 0.005 = 0.01 K
b) ΔTf = Kf x i x molality = Kf x 1 x 0.005 = 0.005 K
c) ΔTf = Kf x i x molality = Kf x 3 x 0.005 = 0.015 K
d) ΔTf = Kf x i x molality = Kf x 2 x 0.005 = 0.01 K
Since solution a) and d) have the same van't Hoff factor (i = 2) and the same molality (0.005 m), they will have the same freezing point depression. Therefore, the solution with the highest van't Hoff factor (i = 3) is solution c). Hence, the solution with the minimum freezing point is solution a) (0.01 K).
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Community Answer
Which of the following aqueous solution has minimum freezing point ? [...
∆Tf is directly proportional to molality.
where ∆Tf is the depression in freezing point.
where ∆Tf is the depression in freezing point.
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Which of the following aqueous solution has minimum freezing point ? [1991]a)0.01 m NaClb)0.005 m C2H5OHc)0.005 m MgI2d)0.005 m MgSO4.Correct answer is option 'A'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Which of the following aqueous solution has minimum freezing point ? [1991]a)0.01 m NaClb)0.005 m C2H5OHc)0.005 m MgI2d)0.005 m MgSO4.Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following aqueous solution has minimum freezing point ? [1991]a)0.01 m NaClb)0.005 m C2H5OHc)0.005 m MgI2d)0.005 m MgSO4.Correct answer is option 'A'. Can you explain this answer?.
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