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If a sample of ferric sulphate Fe2(SO4)3 contains 7.2 moles of O-atoms ,then the number of S-atoms in the given sample are (A)1.8Nsubscript A (B)0.9NsubscriptA (C)3.6NsubscriptA (D)3.1NsubscriptA?
Most Upvoted Answer
If a sample of ferric sulphate Fe2(SO4)3 contains 7.2 moles of O-atoms...
12 oxygen atom = 7.2 mole
1 oxygen atom =7.2÷12
3 atom of sulphur =0.6×3 mole of oxygen
i.e.1.8 N no. of atoms
as atoms of sulphur r comparing to oxygen atom so it's saying subscript of A
1 oxygen atom =7.2÷12
3 atom of sulphur =0.6×3 mole of oxygen
i.e.1.8 N no. of atoms
as atoms of sulphur r comparing to oxygen atom so it's saying subscript of A
Community Answer
If a sample of ferric sulphate Fe2(SO4)3 contains 7.2 moles of O-atoms...
Calculation of moles of O-atoms
The molar mass of Fe2(SO4)3 can be calculated as follows:
Fe2(SO4)3 = 2(55.845) + 3(32.066 + 4(15.999)) = 399.88 g/mol
Therefore, 7.2 moles of O-atoms would weigh:
7.2 mol x 3 x 15.999 g/mol = 1,151.94 g
Calculation of moles of S-atoms
The molecular formula of ferric sulphate Fe2(SO4)3 contains 3 sulphur atoms. Therefore, the moles of S-atoms in the sample can be calculated as follows:
Moles of S-atoms = (mass of sample/molar mass) x 3
Assuming a sample mass of 1 mole, we get:
Moles of S-atoms = (1/399.88) x 3 = 0.0075 moles
If we assume that the sample contains x moles of S-atoms, then we can set up the following equation:
x/(0.0075) = 7.2
Solving for x, we get:
x = 0.054 moles
Finally, the number of S-atoms in the given sample can be calculated as follows:
Number of S-atoms = moles of S-atoms x Avogadro's number
Number of S-atoms = 0.054 x 6.022 x 10^23 = 3.25 x 10^22
Therefore, the answer is option D) 3.1NsubscriptA (since this is the closest option to the calculated value of 3.25NsubscriptA).
The molar mass of Fe2(SO4)3 can be calculated as follows:
Fe2(SO4)3 = 2(55.845) + 3(32.066 + 4(15.999)) = 399.88 g/mol
Therefore, 7.2 moles of O-atoms would weigh:
7.2 mol x 3 x 15.999 g/mol = 1,151.94 g
Calculation of moles of S-atoms
The molecular formula of ferric sulphate Fe2(SO4)3 contains 3 sulphur atoms. Therefore, the moles of S-atoms in the sample can be calculated as follows:
Moles of S-atoms = (mass of sample/molar mass) x 3
Assuming a sample mass of 1 mole, we get:
Moles of S-atoms = (1/399.88) x 3 = 0.0075 moles
If we assume that the sample contains x moles of S-atoms, then we can set up the following equation:
x/(0.0075) = 7.2
Solving for x, we get:
x = 0.054 moles
Finally, the number of S-atoms in the given sample can be calculated as follows:
Number of S-atoms = moles of S-atoms x Avogadro's number
Number of S-atoms = 0.054 x 6.022 x 10^23 = 3.25 x 10^22
Therefore, the answer is option D) 3.1NsubscriptA (since this is the closest option to the calculated value of 3.25NsubscriptA).
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If a sample of ferric sulphate Fe2(SO4)3 contains 7.2 moles of O-atoms ,then the number of S-atoms in the given sample are (A)1.8Nsubscript A (B)0.9NsubscriptA (C)3.6NsubscriptA (D)3.1NsubscriptA?
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If a sample of ferric sulphate Fe2(SO4)3 contains 7.2 moles of O-atoms ,then the number of S-atoms in the given sample are (A)1.8Nsubscript A (B)0.9NsubscriptA (C)3.6NsubscriptA (D)3.1NsubscriptA? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If a sample of ferric sulphate Fe2(SO4)3 contains 7.2 moles of O-atoms ,then the number of S-atoms in the given sample are (A)1.8Nsubscript A (B)0.9NsubscriptA (C)3.6NsubscriptA (D)3.1NsubscriptA? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If a sample of ferric sulphate Fe2(SO4)3 contains 7.2 moles of O-atoms ,then the number of S-atoms in the given sample are (A)1.8Nsubscript A (B)0.9NsubscriptA (C)3.6NsubscriptA (D)3.1NsubscriptA?.
If a sample of ferric sulphate Fe2(SO4)3 contains 7.2 moles of O-atoms ,then the number of S-atoms in the given sample are (A)1.8Nsubscript A (B)0.9NsubscriptA (C)3.6NsubscriptA (D)3.1NsubscriptA? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If a sample of ferric sulphate Fe2(SO4)3 contains 7.2 moles of O-atoms ,then the number of S-atoms in the given sample are (A)1.8Nsubscript A (B)0.9NsubscriptA (C)3.6NsubscriptA (D)3.1NsubscriptA? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If a sample of ferric sulphate Fe2(SO4)3 contains 7.2 moles of O-atoms ,then the number of S-atoms in the given sample are (A)1.8Nsubscript A (B)0.9NsubscriptA (C)3.6NsubscriptA (D)3.1NsubscriptA?.
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