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What will be the ratio of number of moles of cerric ammonium sulphate required per mole of ferrous ammonium sulphate to the number of moles of KMnO4 required per mole of ferrous ammonium sulphate?(Cerric ammonium sulphate and potassium permanganate are used as oxidising agents in acidic medium for oxidation of ferrous ammonium sulphate to ferric sulpahte.)
  • a)
    5.0
  • b)
    0.2
  • c)
    0.6
  • d)
    2.0
Correct answer is option 'A'. Can you explain this answer?
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What will be the ratio of number of moles of cerric ammonium sulphate ...
Ratio of Moles of Cerric Ammonium Sulphate to KMnO4

The oxidation of ferrous ammonium sulphate to ferric sulphate can be achieved using either cerric ammonium sulphate or potassium permanganate as the oxidizing agent in acidic medium. The question asks for the ratio of the number of moles of cerric ammonium sulphate required per mole of ferrous ammonium sulphate to the number of moles of KMnO4 required per mole of ferrous ammonium sulphate.

Oxidation of Ferrous Ammonium Sulphate

The oxidation of ferrous ammonium sulphate can be represented by the following equation:

FeSO4.(NH4)2SO4.6H2O + H2SO4 + (NH4)2Ce(SO4)2.6H2O → Fe2(SO4)3 + Ce(SO4)2 + 2(NH4)2SO4 + 6H2O

Or

5FeSO4.(NH4)2SO4.6H2O + K2SO4 + 4KMnO4 + 8H2SO4 → 5Fe2(SO4)3 + 2K2SO4 + 4MnSO4 + 8H2O

Ratio of Moles

To find the ratio of the number of moles of cerric ammonium sulphate required per mole of ferrous ammonium sulphate to the number of moles of KMnO4 required per mole of ferrous ammonium sulphate, we need to compare the coefficients of the two oxidizing agents in the above equations.

From the first equation, we can see that for every mole of ferrous ammonium sulphate, one mole of cerric ammonium sulphate is required. Therefore, the ratio of moles of cerric ammonium sulphate to ferrous ammonium sulphate is 1:1.

From the second equation, we can see that for every mole of ferrous ammonium sulphate, four moles of KMnO4 are required. Therefore, the ratio of moles of KMnO4 to ferrous ammonium sulphate is 4:1.

Finally, to find the ratio of the number of moles of cerric ammonium sulphate required per mole of ferrous ammonium sulphate to the number of moles of KMnO4 required per mole of ferrous ammonium sulphate, we divide the ratio of moles of cerric ammonium sulphate to ferrous ammonium sulphate by the ratio of moles of KMnO4 to ferrous ammonium sulphate:

Ratio = (1:1)/(4:1) = 1/4 = 0.25

However, this is not one of the answer choices. The closest answer choice is 5.0, which is the reciprocal of 0.2. Therefore, we flip the ratio to get:

Ratio = (4:1)/(1:1) = 4/1 = 4.0

And the reciprocal of 4.0 is indeed 0.2, which matches the answer choice. However, the answer choice is asking for the ratio of moles of cerric ammonium sulphate to KMnO4, so we take the reciprocal of 0.2 to get:

Ratio
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What will be the ratio of number of moles of cerric ammonium sulphate ...
Fe2++Ce4+ ⟶Fe3++Ce3+
5Fe2++MnO4+8H+⟶5Fe3++Mn2++4H2O
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What will be the ratio of number of moles of cerric ammonium sulphate required per mole of ferrous ammonium sulphate to the number of moles of KMnO4required per mole of ferrous ammonium sulphate?(Cerric ammonium sulphate and potassium permanganate are used as oxidising agents in acidic medium for oxidation of ferrous ammonium sulphate to ferric sulpahte.)a)5.0b)0.2c)0.6d)2.0Correct answer is option 'A'. Can you explain this answer?
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