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A thin spherical conducting shell of radius R has charge q. Another charge Q is placed at the centre of the shell. The electrostatic potential at a point P at a distance R/2 from the centre of the shell is
  • a)
    2Q/4πε₀R
  • b)
    2(q+Q)/4πε₀R
  • c)
    2Q/4πε₀R - 2q/4πε₀R
  • d)
    2Q/4πε₀R + q/4πε₀R
Correct answer is option 'D'. Can you explain this answer?
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A thin spherical conducting shell of radius R has charge q. Another ch...
D is the correct answer
Explanation:
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A thin spherical conducting shell of radius R has charge q. Another ch...
Since the charge Q is at the center of the shell, it will induce an equal and opposite charge (-Q) on the inner surface of the shell and a charge (+Q) on the outer surface of the shell. This is due to the principle of superposition of charges.

Now, we can consider the charge distribution on the shell as a combination of two charges - the original charge q on the shell and the induced charge +Q on the outer surface of the shell.

Using the formula for the potential due to a point charge (V = kQ/r), the potential at point P due to the charge +Q on the outer surface of the shell is:

V1 = kQ/(R/2)

Using the formula for the potential due to a uniformly charged spherical shell (V = kQ/R), the potential at point P due to the charge q on the shell is:

V2 = kq/R

The total potential at point P is the sum of these two potentials:

V = V1 + V2 = kQ/(R/2) + kq/R

Simplifying this expression, we get:

V = 2kQ/R + kq/R

= (2Q/4πε0R) + (q/4πε0R)

= (2Q+q)/4πε0R

Therefore, the electrostatic potential at point P is (2Q+q)/4πε0R.
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A thin spherical conducting shell of radius R has charge q. Another charge Q is placed at the centre of the shell. The electrostatic potential at a point P at a distance R/2 from the centre of the shell isa)2Q/4πε₀Rb)2(q+Q)/4πε₀Rc)2Q/4πε₀R - 2q/4πε₀Rd)2Q/4πε₀R + q/4πε₀RCorrect answer is option 'D'. Can you explain this answer?
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A thin spherical conducting shell of radius R has charge q. Another charge Q is placed at the centre of the shell. The electrostatic potential at a point P at a distance R/2 from the centre of the shell isa)2Q/4πε₀Rb)2(q+Q)/4πε₀Rc)2Q/4πε₀R - 2q/4πε₀Rd)2Q/4πε₀R + q/4πε₀RCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A thin spherical conducting shell of radius R has charge q. Another charge Q is placed at the centre of the shell. The electrostatic potential at a point P at a distance R/2 from the centre of the shell isa)2Q/4πε₀Rb)2(q+Q)/4πε₀Rc)2Q/4πε₀R - 2q/4πε₀Rd)2Q/4πε₀R + q/4πε₀RCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A thin spherical conducting shell of radius R has charge q. Another charge Q is placed at the centre of the shell. The electrostatic potential at a point P at a distance R/2 from the centre of the shell isa)2Q/4πε₀Rb)2(q+Q)/4πε₀Rc)2Q/4πε₀R - 2q/4πε₀Rd)2Q/4πε₀R + q/4πε₀RCorrect answer is option 'D'. Can you explain this answer?.
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