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A thin spherical conducting shell of radius R has charge q. Another charge Q is placed at the centre of the shell. The electrostatic potential at a point P at a distance R/2 from the centre of the shell is
  • a)
    2Q/4πε₀R
  • b)
    2(q+Q)/4πε₀R
  • c)
    2Q/4πε₀R - 2q/4πε₀R
  • d)
    2Q/4πε₀R + q/4πε₀R
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
A thin spherical conducting shell of radius R has charge q. Another ch...
Since the conductor is an equipotential surface, the potential at any point inside the shell is the same as the potential at the center of the shell. Therefore, the potential at point P is the same as the potential at the center of the shell due to charge Q.

Using the formula for potential due to a point charge, we have:

V = kQ/r

where k is the Coulomb constant, Q is the charge and r is the distance from the charge.

In this case, Q is at the center of the shell, so r = 0.5R.

Therefore, the potential at point P is:

V = kQ/(0.5R) = 2kQ/R

Substituting the value of k as 1/4πε0, where ε0 is the permittivity of free space, we get:

V = 2Q/(4πε0R)

Therefore, the correct answer is option (a) 2Q/4πε0R.
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A thin spherical conducting shell of radius R has charge q. Another charge Q is placed at the centre of the shell. The electrostatic potential at a point P at a distance R/2 from the centre of the shell isa)2Q/4πεRb)2(q+Q)/4πεRc)2Q/4πεR - 2q/4πεRd)2Q/4πεR + q/4πεRCorrect answer is option 'D'. Can you explain this answer?
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A thin spherical conducting shell of radius R has charge q. Another charge Q is placed at the centre of the shell. The electrostatic potential at a point P at a distance R/2 from the centre of the shell isa)2Q/4πεRb)2(q+Q)/4πεRc)2Q/4πεR - 2q/4πεRd)2Q/4πεR + q/4πεRCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A thin spherical conducting shell of radius R has charge q. Another charge Q is placed at the centre of the shell. The electrostatic potential at a point P at a distance R/2 from the centre of the shell isa)2Q/4πεRb)2(q+Q)/4πεRc)2Q/4πεR - 2q/4πεRd)2Q/4πεR + q/4πεRCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A thin spherical conducting shell of radius R has charge q. Another charge Q is placed at the centre of the shell. The electrostatic potential at a point P at a distance R/2 from the centre of the shell isa)2Q/4πεRb)2(q+Q)/4πεRc)2Q/4πεR - 2q/4πεRd)2Q/4πεR + q/4πεRCorrect answer is option 'D'. Can you explain this answer?.
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