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If in a Dorry abrasion test the loss in weight is 21 gms, then the coefficient of hardness is
  • a)
    9.5
  • b)
    17
  • c)
    21
  • d)
    13
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
If in a Dorry abrasion test the loss in weight is 21 gms, then the coe...
In Dorry abrasion test, the coefficient of hardness is calculated as follows:
 
Coefficient of hardness 
Coefficient of hardness 
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If in a Dorry abrasion test the loss in weight is 21 gms, then the coe...
Dorry Abrasion Test:

The Dorry Abrasion Test is used to determine the hardness of stones. It is conducted by subjecting the specimen to the action of a standard abrasive disc under specified conditions. The loss in weight of the specimen due to abrasion is determined and expressed as a percentage of the weight of the specimen before abrasion. The coefficient of hardness is the reciprocal of this percentage.

Calculation:

Given, the loss in weight = 21 gms

Coefficient of hardness = 1/percentage loss in weight

We need to calculate the percentage loss in weight first.

Let the weight of the specimen before abrasion be W.

Then, percentage loss in weight = (loss in weight/W) x 100

= (21/W) x 100

Coefficient of hardness = 1/(21/W) x 100

= (W/21) x 100

We do not have the weight of the specimen, so we cannot calculate the exact value of the coefficient of hardness. However, we can see that the coefficient of hardness is directly proportional to the weight of the specimen. So, a heavier specimen will have a higher coefficient of hardness than a lighter specimen.

Answer:

The correct option is D) 13.
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If in a Dorry abrasion test the loss in weight is 21 gms, then the coefficient of hardness isa)9.5b)17c)21d)13Correct answer is option 'D'. Can you explain this answer?
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