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The square root of the number 5 + 12i is
  • a)
    (3 + 2i)
  • b)
    (3 - 2i)
  • c)
    (3 + 2i)
  • d)
    none
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The square root of the number 5 + 12i isa)(3 + 2i)b)(3 - 2i)c) (3 + 2i...
Ans.

Option (c)

Suppose that a+bi is a square root of 5 + 12i.
Then, (a+bi)^2 = (a^2 - b^2) + (2ab)i = 5 + 12i.
Equate real and imaginary parts:
a^2 - b^2 = 5
2ab = 12 ==> b = 6/a.

So, a^2 - (6/a)^2 = 5
==> a^2 - 36/a^2 = 5
==> a^4 -5a^2 - 36 = 0.
==> (a^2 -9)(a^2 + 4) = 0.
Since a must be real, a = 3 or -3.
This gives b = 2 or -2, respectively.

Thus, we have two square roots: 3+2i or -3-2i.
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Most Upvoted Answer
The square root of the number 5 + 12i isa)(3 + 2i)b)(3 - 2i)c) (3 + 2i...
Ans.

Option (c)

Suppose that a+bi is a square root of 5 + 12i.
Then, (a+bi)^2 = (a^2 - b^2) + (2ab)i = 5 + 12i.
Equate real and imaginary parts:
a^2 - b^2 = 5
2ab = 12 ==> b = 6/a.

So, a^2 - (6/a)^2 = 5
==> a^2 - 36/a^2 = 5
==> a^4 -5a^2 - 36 = 0.
==> (a^2 -9)(a^2 + 4) = 0.
Since a must be real, a = 3 or -3.
This gives b = 2 or -2, respectively.

Thus, we have two square roots: 3+2i or -3-2i.

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