a particle is projected at some angle with velocity 50 metre per secon...
**Given Information:**
- Initial velocity of the particle, u = 50 m/s
- Height of the wall, h = 20 m
- Time taken to cross the wall, t = 4 seconds
**To find:**
The angle of projection of the particle.
**Assumptions:**
- We will consider the motion of the particle in a vertical plane only, neglecting the effects of air resistance.
- The acceleration due to gravity, g = 9.8 m/s², is constant throughout the motion.
- The particle is projected from the ground level.
**Approach:**
We can solve this problem using the equations of motion in two dimensions.
1. Let's break the initial velocity u into its horizontal and vertical components.
- The horizontal component, uₓ, remains constant throughout the motion, as there is no horizontal acceleration. Therefore, uₓ = u * cosθ, where θ is the angle of projection.
- The vertical component, uᵧ, changes due to the acceleration due to gravity. Therefore, uᵧ = u * sinθ.
2. The time of flight, T, can be calculated using the equation of motion:
- h = uᵧ * t - 0.5 * g * t²
3. We can solve this equation for T by substituting the given values of h, uᵧ, g, and t. This will give us a quadratic equation in T.
4. The horizontal range, R, can be calculated using the equation of motion:
- R = uₓ * T
5. We can solve this equation for R by substituting the given values of uₓ and T.
6. Finally, we can find the angle of projection θ by using the equation:
- θ = tan⁻¹(R/h)
**Calculations:**
1. Finding uₓ and uᵧ:
- uₓ = 50 * cosθ
- uᵧ = 50 * sinθ
2. Finding T:
- h = uᵧ * t - 0.5 * g * t²
- 20 = (50 * sinθ) * 4 - 0.5 * 9.8 * 4²
- 20 = 200 * sinθ - 78.4
- 200 * sinθ = 98.4
- sinθ = 0.492
3. Finding R:
- R = uₓ * T
- R = (50 * cosθ) * T
4. Substituting sinθ = 0.492 and solving for R:
- R = (50 * cos⁻¹(0.492)) * T
5. Substituting T = 4 seconds and solving for R:
- R = (50 * cos⁻¹(0.492)) * 4
6. Finally, finding the angle of projection θ:
- θ = tan⁻¹(R/h)
- θ = tan⁻¹(((50 * cos⁻¹(0.492)) * 4)/20)
**Conclusion:**
By solving the above equation, we can find the angle of projection of the particle.
a particle is projected at some angle with velocity 50 metre per secon...
Take vertical motion of the projectile 20=50sin¢×t-1/2gt^2
so, 50sin¢=20/t+1/2gt
=20/4+1/2×10×4
=25
so sin¢=1/2
and ¢=30 degree
answer is 30 degree