The velocity of a particle moving with constant acceleration at an ins...
In the question it should be “……body at an instant is 10 m/s……”
Acceleration = (v - u) / t
= (20 - 10) / 5
= 2 m/s^2
Acceleration of body is 2 m/s^2
Now,
v = u + at
10 = u + (2 � 3)
u = 10 - 6
u = 4 m/s
Velocity 3 seconds before was 4 m/s
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The velocity of a particle moving with constant acceleration at an ins...
Given data:
Initial velocity (u) = 10 m/s
Final velocity (v) = 20 m/s
Time interval (t) = 5 s
Using the formula:
v = u + at
Where:
v = final velocity
u = initial velocity
a = acceleration
t = time
Calculating the acceleration:
v = u + at
20 = 10 + a * 5
20 - 10 = 5a
10 = 5a
a = 2 m/s²
Calculating the time before t0:
Given that the time interval is 5 seconds, and we want to find the velocity 3 seconds before t0. Therefore, the time before t0 is (5 - 3) = 2 seconds.
Calculating the velocity at 2 seconds before t0:
Using the formula v = u + at, we can substitute the known values:
v = u + at
v = 10 + 2 * 2
v = 10 + 4
v = 14 m/s
Explanation:
To find the velocity at a specific time, we can use the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time interval.
In this case, we are given the initial velocity (10 m/s) and the final velocity (20 m/s) after a time interval of 5 seconds. By substituting these values into the equation, we can solve for the acceleration, which is found to be 2 m/s².
To find the velocity 3 seconds before t0, we need to subtract the time interval (5 seconds) by the given time (3 seconds) to get 2 seconds. We can then substitute the values of u, a, and t into the equation to calculate the velocity at that time. The velocity at 2 seconds before t0 is found to be 14 m/s.
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