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A lady is traveling at the speed of 20km/hr.if she returns back with high speed and average speed of journey is 24km/h.find the return speed ?
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A lady is traveling at the speed of 20km/hr.if she returns back with h...
Given Information:
- Initial speed of the lady = 20 km/hr
- Average speed of the journey = 24 km/hr
Calculating the Return Speed:
Let's assume the speed of the lady on her return journey as x km/hr.
As per the question, the average speed of the entire journey is 24 km/hr. We can use the formula:
Average speed = Total distance covered / Total time taken
Let's assume the total distance as 'd' km and the total time taken as 't' hours.
- While going: time taken = d / 20
- While returning: time taken = d / x
- Total journey time = d/20 + d/x = d(1/20 + 1/x)
- Average speed = total distance / total time
- 24 = d / [d(1/20 + 1/x)]
- 24 = 1 / [(1/20) + (1/x)]
- 1 / 24 = (1/20) + (1/x)
- 1/x = 1/24 - 1/20
- 1/x = 1/120
- x = 120 km/hr
Answer:
Hence, the speed of the lady on her return journey is 120 km/hr.
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A lady is traveling at the speed of 20km/hr.if she returns back with high speed and average speed of journey is 24km/h.find the return speed ?
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