Calculate the mass of sodium which contains same number of atoms as ar...
Calculation of Mass of Sodium with Same Number of Atoms as in 4g of Calcium
Given:
- Atomic mass of sodium (Na) = 23
- Atomic mass of calcium (Ca) = 40
- Mass of calcium (Ca) = 4g
Step 1: Calculate the Number of Atoms in 4g of Calcium
Number of moles of calcium (Ca):
$$\text{Moles} = \frac{\text{Mass}}{\text{Molar mass}}$$
$$\text{Moles of Ca} = \frac{4g}{40g/mol} = 0.1mol$$
Number of atoms of calcium (Ca):
$$\text{Number of atoms} = \text{Moles} \times \text{Avogadro's number}$$
$$\text{Number of atoms of Ca} = 0.1mol \times 6.022 \times 10^{23} \text{atoms/mol} = 6.022 \times 10^{22} \text{atoms}$$
Step 2: Calculate the Mass of Sodium with Same Number of Atoms as in 4g of Calcium
Number of atoms of sodium (Na):
$$\text{Number of atoms of Na} = \text{Number of atoms of Ca}$$
$$\text{Number of atoms of Na} = 6.022 \times 10^{22} \text{atoms}$$
Number of moles of sodium (Na):
$$\text{Moles of Na} = \frac{\text{Number of atoms of Na}}{\text{Avogadro's number}}$$
$$\text{Moles of Na} = \frac{6.022 \times 10^{22} \text{atoms}}{6.022 \times 10^{23} \text{atoms/mol}} = 0.1mol$$
Mass of sodium (Na):
$$\text{Mass of Na} = \text{Moles of Na} \times \text{Molar mass of Na}$$
$$\text{Mass of Na} = 0.1mol \times 23g/mol = 2.3g$$
Step 3: Answer
Therefore, the mass of sodium (Na) which contains the same number of atoms as are present in 4g of calcium (Ca) is 2.3g.