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Calculate the mass of sodium which contains same number of atoms as are present in 4 gram of calcium atomic mass of sodium and calcium are 23 and 40 respectively?
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Calculation of Mass of Sodium with Same Number of Atoms as in 4g of Calcium


Given:


  • Atomic mass of sodium (Na) = 23

  • Atomic mass of calcium (Ca) = 40

  • Mass of calcium (Ca) = 4g



Step 1: Calculate the Number of Atoms in 4g of Calcium


Number of moles of calcium (Ca):


$$\text{Moles} = \frac{\text{Mass}}{\text{Molar mass}}$$

$$\text{Moles of Ca} = \frac{4g}{40g/mol} = 0.1mol$$


Number of atoms of calcium (Ca):


$$\text{Number of atoms} = \text{Moles} \times \text{Avogadro's number}$$

$$\text{Number of atoms of Ca} = 0.1mol \times 6.022 \times 10^{23} \text{atoms/mol} = 6.022 \times 10^{22} \text{atoms}$$

Step 2: Calculate the Mass of Sodium with Same Number of Atoms as in 4g of Calcium


Number of atoms of sodium (Na):


$$\text{Number of atoms of Na} = \text{Number of atoms of Ca}$$

$$\text{Number of atoms of Na} = 6.022 \times 10^{22} \text{atoms}$$

Number of moles of sodium (Na):


$$\text{Moles of Na} = \frac{\text{Number of atoms of Na}}{\text{Avogadro's number}}$$

$$\text{Moles of Na} = \frac{6.022 \times 10^{22} \text{atoms}}{6.022 \times 10^{23} \text{atoms/mol}} = 0.1mol$$

Mass of sodium (Na):


$$\text{Mass of Na} = \text{Moles of Na} \times \text{Molar mass of Na}$$

$$\text{Mass of Na} = 0.1mol \times 23g/mol = 2.3g$$

Step 3: Answer


Therefore, the mass of sodium (Na) which contains the same number of atoms as are present in 4g of calcium (Ca) is 2.3g.
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Calculate the mass of sodium which contains same number of atoms as ar...
2.3g
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Calculate the mass of sodium which contains same number of atoms as are present in 4 gram of calcium atomic mass of sodium and calcium are 23 and 40 respectively?
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