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One Integer Value Correct Type
Direction (Q. Nos. 28-30) This section contains 3 questions. When worked out will result in an integer from 0 to 9 (both inclusive).
Q.
An ether, on treatment with sulphuric acid and sodium iodide, yields a single iodoalkane that contains 74.7% iodine by weight. How many carbon atoms are present in a molecule of this ether ? [Molar mass of I = 127]
Correct answer is '6'. Can you explain this answer?
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One Integer Value Correct TypeDirection (Q. Nos. 28-30) This section c...
From % of iodine, formula of iodoalkane is derived as C3H7I. Hence, ether is C3H7OC3H7.
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One Integer Value Correct TypeDirection (Q. Nos. 28-30) This section c...
Solution:
Given:
- The iodoalkane obtained from the reaction contains 74.7% iodine by weight.
- Molar mass of iodine (I) = 127.
To find:
- The number of carbon atoms in the molecule of the ether.
Step 1: Determine the molecular weight of the iodoalkane.
Since the iodoalkane contains 74.7% iodine by weight, the remaining percentage of the molecular weight is due to carbon atoms. Therefore, the weight percentage of carbon in the iodoalkane is given by:
Weight percentage of carbon = 100% - 74.7% = 25.3%
Step 2: Convert the weight percentage of carbon to molar ratio.
To convert the weight percentage of carbon to molar ratio, we need to know the molar masses of both carbon and iodine. The molar mass of iodine is given as 127, but we need to find the molar mass of carbon.
Step 3: Determine the molar mass of carbon.
The molecular weight of the iodoalkane is the sum of the molar masses of its constituent atoms. Let's assume the iodoalkane has 'x' carbon atoms.
Molar mass of iodoalkane = (x * molar mass of carbon) + (1 * molar mass of iodine)
Since the molecular weight of the iodoalkane is not given, we need to find it using the weight percentage of carbon and iodine.
Step 4: Set up an equation using the weight percentage of carbon and iodine.
Weight percentage of carbon = (x * molar mass of carbon) / (x * molar mass of carbon + molar mass of iodine)
Substituting the given values:
25.3% = (x * molar mass of carbon) / (x * molar mass of carbon + 127)
Step 5: Solve the equation for 'x'.
To solve the equation, we can cross-multiply and rearrange the terms:
25.3% * (x * molar mass of carbon + 127) = x * molar mass of carbon
0.253 * (x * molar mass of carbon) + 0.253 * 127 = x * molar mass of carbon
0.253 * 127 = (x * molar mass of carbon) - 0.253 * (x * molar mass of carbon)
32.131 = x * molar mass of carbon * (1 - 0.253)
32.131 = x * molar mass of carbon * 0.747
Step 6: Simplify the equation.
Dividing both sides of the equation by 0.747:
32.131 / 0.747 = x * molar mass of carbon
43.04 = x * molar mass of carbon
Step 7: Substitute the molar mass of carbon.
Since the molar mass of carbon is not given, we need to find it. The molar mass of carbon is approximately 12.01 g/mol.
43.04 = x * 12.01
Step 8: Solve for 'x'.
Dividing both sides
Given:
- The iodoalkane obtained from the reaction contains 74.7% iodine by weight.
- Molar mass of iodine (I) = 127.
To find:
- The number of carbon atoms in the molecule of the ether.
Step 1: Determine the molecular weight of the iodoalkane.
Since the iodoalkane contains 74.7% iodine by weight, the remaining percentage of the molecular weight is due to carbon atoms. Therefore, the weight percentage of carbon in the iodoalkane is given by:
Weight percentage of carbon = 100% - 74.7% = 25.3%
Step 2: Convert the weight percentage of carbon to molar ratio.
To convert the weight percentage of carbon to molar ratio, we need to know the molar masses of both carbon and iodine. The molar mass of iodine is given as 127, but we need to find the molar mass of carbon.
Step 3: Determine the molar mass of carbon.
The molecular weight of the iodoalkane is the sum of the molar masses of its constituent atoms. Let's assume the iodoalkane has 'x' carbon atoms.
Molar mass of iodoalkane = (x * molar mass of carbon) + (1 * molar mass of iodine)
Since the molecular weight of the iodoalkane is not given, we need to find it using the weight percentage of carbon and iodine.
Step 4: Set up an equation using the weight percentage of carbon and iodine.
Weight percentage of carbon = (x * molar mass of carbon) / (x * molar mass of carbon + molar mass of iodine)
Substituting the given values:
25.3% = (x * molar mass of carbon) / (x * molar mass of carbon + 127)
Step 5: Solve the equation for 'x'.
To solve the equation, we can cross-multiply and rearrange the terms:
25.3% * (x * molar mass of carbon + 127) = x * molar mass of carbon
0.253 * (x * molar mass of carbon) + 0.253 * 127 = x * molar mass of carbon
0.253 * 127 = (x * molar mass of carbon) - 0.253 * (x * molar mass of carbon)
32.131 = x * molar mass of carbon * (1 - 0.253)
32.131 = x * molar mass of carbon * 0.747
Step 6: Simplify the equation.
Dividing both sides of the equation by 0.747:
32.131 / 0.747 = x * molar mass of carbon
43.04 = x * molar mass of carbon
Step 7: Substitute the molar mass of carbon.
Since the molar mass of carbon is not given, we need to find it. The molar mass of carbon is approximately 12.01 g/mol.
43.04 = x * 12.01
Step 8: Solve for 'x'.
Dividing both sides
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One Integer Value Correct TypeDirection (Q. Nos. 28-30) This section contains 3 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.An ether, on treatment with sulphuric acid and sodium iodide, yields a single iodoalkane that contains 74.7% iodine by weight. How many carbon atoms are present in a molecule of this ether ? [Molar mass of I = 127]Correct answer is '6'. Can you explain this answer?
Question Description
One Integer Value Correct TypeDirection (Q. Nos. 28-30) This section contains 3 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.An ether, on treatment with sulphuric acid and sodium iodide, yields a single iodoalkane that contains 74.7% iodine by weight. How many carbon atoms are present in a molecule of this ether ? [Molar mass of I = 127]Correct answer is '6'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about One Integer Value Correct TypeDirection (Q. Nos. 28-30) This section contains 3 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.An ether, on treatment with sulphuric acid and sodium iodide, yields a single iodoalkane that contains 74.7% iodine by weight. How many carbon atoms are present in a molecule of this ether ? [Molar mass of I = 127]Correct answer is '6'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One Integer Value Correct TypeDirection (Q. Nos. 28-30) This section contains 3 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.An ether, on treatment with sulphuric acid and sodium iodide, yields a single iodoalkane that contains 74.7% iodine by weight. How many carbon atoms are present in a molecule of this ether ? [Molar mass of I = 127]Correct answer is '6'. Can you explain this answer?.
One Integer Value Correct TypeDirection (Q. Nos. 28-30) This section contains 3 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.An ether, on treatment with sulphuric acid and sodium iodide, yields a single iodoalkane that contains 74.7% iodine by weight. How many carbon atoms are present in a molecule of this ether ? [Molar mass of I = 127]Correct answer is '6'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about One Integer Value Correct TypeDirection (Q. Nos. 28-30) This section contains 3 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.An ether, on treatment with sulphuric acid and sodium iodide, yields a single iodoalkane that contains 74.7% iodine by weight. How many carbon atoms are present in a molecule of this ether ? [Molar mass of I = 127]Correct answer is '6'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One Integer Value Correct TypeDirection (Q. Nos. 28-30) This section contains 3 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.An ether, on treatment with sulphuric acid and sodium iodide, yields a single iodoalkane that contains 74.7% iodine by weight. How many carbon atoms are present in a molecule of this ether ? [Molar mass of I = 127]Correct answer is '6'. Can you explain this answer?.
Solutions for One Integer Value Correct TypeDirection (Q. Nos. 28-30) This section contains 3 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.An ether, on treatment with sulphuric acid and sodium iodide, yields a single iodoalkane that contains 74.7% iodine by weight. How many carbon atoms are present in a molecule of this ether ? [Molar mass of I = 127]Correct answer is '6'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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