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This section contains 6 questions. Each question, when worked out will result in one integer from 0 to 9(both inclusive).
Two friends have equal number of sons. There are 3 tickets for a cricket match which are to be distributed among the sons. The probability that two tickets go to the sons of one and one tickets goes to the sons of other is 6/7 . Then total number of boys is equal to (sum of son of each friend).
Two friends have equal number of sons. There are 3 tickets for a cricket match which are to be distributed among the sons. The probability that two tickets go to the sons of one and one tickets goes to the sons of other is 6/7 . Then total number of boys is equal to (sum of son of each friend).
Correct answer is '8'. Can you explain this answer?
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This section contains 6 questions. Each question, when worked out will...
let each friend has n sons.
∴ 3 tickets can be distributed among 2n sons in 2nC3 ways.
The number of ways distributing 3 tickets such that two tickets go to the sons of one and one tickets goes to sons of the other.
nC2 x nC1 + nC1 x nC2 = 2 x nC1 x nC2 probability that two tickets go to the sons of one and one tickets goes the sons of the other
∴ 3 tickets can be distributed among 2n sons in 2nC3 ways.
The number of ways distributing 3 tickets such that two tickets go to the sons of one and one tickets goes to sons of the other.
nC2 x nC1 + nC1 x nC2 = 2 x nC1 x nC2 probability that two tickets go to the sons of one and one tickets goes the sons of the other
But from the question
hence total number of boys = 8
Most Upvoted Answer
This section contains 6 questions. Each question, when worked out will...
Analysis:
Let's assume that each friend has 'x' sons. So, the total number of sons will be 2x. We need to find the value of 'x'.
According to the given condition, the probability of two tickets going to the sons of one friend and one ticket going to the sons of the other friend is 6/7.
Solution:
Step 1:
Let's distribute the tickets among the sons of the two friends in different ways:
1st friend: 2 tickets
2nd friend: 1 ticket
2nd friend: 2 tickets
1st friend: 1 ticket
Let's calculate the probability for each case.
Case 1: 1st friend: 2 tickets, 2nd friend: 1 ticket
The probability of selecting 2 tickets from the 1st friend's sons is: (xC2)/(2xC2) = x(x-1)/(2x(2x-1)) = (x-1)/(4x-2)
The probability of selecting 1 ticket from the 2nd friend's sons is: (xC1)/(2x-2C1) = x/(2x-2) = x/(2(x-1))
The total probability for this case is: (x-1)/(4x-2) * x/(2(x-1)) = x/(8x-4) = x/(4(2x-1))
Case 2: 2nd friend: 2 tickets, 1st friend: 1 ticket
The probability of selecting 2 tickets from the 2nd friend's sons is: (x(x-1))/(2x(2x-1)) = (x-1)/(4x-2)
The probability of selecting 1 ticket from the 1st friend's sons is: (x)/(2x-2) = x/(2(x-1))
The total probability for this case is: (x-1)/(4x-2) * x/(2(x-1)) = x/(8x-4) = x/(4(2x-1))
Step 2:
According to the given condition, the sum of the probabilities for both cases should be 6/7.
(x/(4(2x-1))) + (x/(4(2x-1))) = 6/7
(2x/(4(2x-1))) = 6/7
Simplifying the equation, we get:
(2x)/(8x-4) = 6/7
14x = 48x - 24
34x = 24
x = 24/34
x = 12/17
Step 3:
The total number of sons will be 2x = 2(12/17) = 24/17.
Since the answer should be an integer, we need to find the value of 'x' which makes the total number of sons an integer.
By trial and error, we find that 'x' = 8 satisfies this condition.
Therefore, the total number of boys is equal to 2x = 2(8) = 16.
Conclusion:
The correct answer is 16, which is
Let's assume that each friend has 'x' sons. So, the total number of sons will be 2x. We need to find the value of 'x'.
According to the given condition, the probability of two tickets going to the sons of one friend and one ticket going to the sons of the other friend is 6/7.
Solution:
Step 1:
Let's distribute the tickets among the sons of the two friends in different ways:
1st friend: 2 tickets
2nd friend: 1 ticket
2nd friend: 2 tickets
1st friend: 1 ticket
Let's calculate the probability for each case.
Case 1: 1st friend: 2 tickets, 2nd friend: 1 ticket
The probability of selecting 2 tickets from the 1st friend's sons is: (xC2)/(2xC2) = x(x-1)/(2x(2x-1)) = (x-1)/(4x-2)
The probability of selecting 1 ticket from the 2nd friend's sons is: (xC1)/(2x-2C1) = x/(2x-2) = x/(2(x-1))
The total probability for this case is: (x-1)/(4x-2) * x/(2(x-1)) = x/(8x-4) = x/(4(2x-1))
Case 2: 2nd friend: 2 tickets, 1st friend: 1 ticket
The probability of selecting 2 tickets from the 2nd friend's sons is: (x(x-1))/(2x(2x-1)) = (x-1)/(4x-2)
The probability of selecting 1 ticket from the 1st friend's sons is: (x)/(2x-2) = x/(2(x-1))
The total probability for this case is: (x-1)/(4x-2) * x/(2(x-1)) = x/(8x-4) = x/(4(2x-1))
Step 2:
According to the given condition, the sum of the probabilities for both cases should be 6/7.
(x/(4(2x-1))) + (x/(4(2x-1))) = 6/7
(2x/(4(2x-1))) = 6/7
Simplifying the equation, we get:
(2x)/(8x-4) = 6/7
14x = 48x - 24
34x = 24
x = 24/34
x = 12/17
Step 3:
The total number of sons will be 2x = 2(12/17) = 24/17.
Since the answer should be an integer, we need to find the value of 'x' which makes the total number of sons an integer.
By trial and error, we find that 'x' = 8 satisfies this condition.
Therefore, the total number of boys is equal to 2x = 2(8) = 16.
Conclusion:
The correct answer is 16, which is
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This section contains 6 questions. Each question, when worked out will result in one integer from 0 to 9(both inclusive).Two friends have equal number of sons. There are 3 tickets for a cricket match which are to be distributed among the sons. The probability that two tickets go to the sons of one and one ticketsgoes to the sons of other is 6/7 . Then total number of boys is equal to (sum of son of each friend).Correct answer is '8'. Can you explain this answer?
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This section contains 6 questions. Each question, when worked out will result in one integer from 0 to 9(both inclusive).Two friends have equal number of sons. There are 3 tickets for a cricket match which are to be distributed among the sons. The probability that two tickets go to the sons of one and one ticketsgoes to the sons of other is 6/7 . Then total number of boys is equal to (sum of son of each friend).Correct answer is '8'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about This section contains 6 questions. Each question, when worked out will result in one integer from 0 to 9(both inclusive).Two friends have equal number of sons. There are 3 tickets for a cricket match which are to be distributed among the sons. The probability that two tickets go to the sons of one and one ticketsgoes to the sons of other is 6/7 . Then total number of boys is equal to (sum of son of each friend).Correct answer is '8'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for This section contains 6 questions. Each question, when worked out will result in one integer from 0 to 9(both inclusive).Two friends have equal number of sons. There are 3 tickets for a cricket match which are to be distributed among the sons. The probability that two tickets go to the sons of one and one ticketsgoes to the sons of other is 6/7 . Then total number of boys is equal to (sum of son of each friend).Correct answer is '8'. Can you explain this answer?.
This section contains 6 questions. Each question, when worked out will result in one integer from 0 to 9(both inclusive).Two friends have equal number of sons. There are 3 tickets for a cricket match which are to be distributed among the sons. The probability that two tickets go to the sons of one and one ticketsgoes to the sons of other is 6/7 . Then total number of boys is equal to (sum of son of each friend).Correct answer is '8'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about This section contains 6 questions. Each question, when worked out will result in one integer from 0 to 9(both inclusive).Two friends have equal number of sons. There are 3 tickets for a cricket match which are to be distributed among the sons. The probability that two tickets go to the sons of one and one ticketsgoes to the sons of other is 6/7 . Then total number of boys is equal to (sum of son of each friend).Correct answer is '8'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for This section contains 6 questions. Each question, when worked out will result in one integer from 0 to 9(both inclusive).Two friends have equal number of sons. There are 3 tickets for a cricket match which are to be distributed among the sons. The probability that two tickets go to the sons of one and one ticketsgoes to the sons of other is 6/7 . Then total number of boys is equal to (sum of son of each friend).Correct answer is '8'. Can you explain this answer?.
Solutions for This section contains 6 questions. Each question, when worked out will result in one integer from 0 to 9(both inclusive).Two friends have equal number of sons. There are 3 tickets for a cricket match which are to be distributed among the sons. The probability that two tickets go to the sons of one and one ticketsgoes to the sons of other is 6/7 . Then total number of boys is equal to (sum of son of each friend).Correct answer is '8'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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