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One Integer Value Correct Type
Direction (Q. Nos. 26-29) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).
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Methyl cyclopentane on treatment with chlorine gas in sunlight undergo free radical chlorination reaction. How many of the above monochlorination products upon treatment with ethanolic KOH solution can give 1-methyl cyclopentane as one of the product?
Correct answer is '3'. Can you explain this answer?
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One Integer Value Correct TypeDirection (Q. Nos. 26-29) This section c...
Only the following chlorination products, upon E2 reaction can give 1-methyl cyclopentene as one of the product.
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One Integer Value Correct TypeDirection (Q. Nos. 26-29) This section c...
Only the following chlorination products, upon E2 reaction can give 1-methyl cyclopentene as one of the product.
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One Integer Value Correct TypeDirection (Q. Nos. 26-29) This section c...
Explanation:
Methyl cyclopentane undergoes free radical chlorination
- When methyl cyclopentane undergoes free radical chlorination with chlorine gas in sunlight, it can form different monochlorination products due to the presence of multiple hydrogen atoms that can be replaced by chlorine.
- The possible monochlorination products include 1-chloromethylcyclopentane, 2-chloromethylcyclopentane, 3-chloromethylcyclopentane, and 4-chloromethylcyclopentane.
Treatment with ethanolic KOH solution
- When these monochlorination products are treated with ethanolic KOH solution, they undergo an elimination reaction to form alkenes.
- In order to form 1-methylcyclopentane upon treatment with ethanolic KOH, the starting monochlorination product should have the chlorine atom at the 3rd position (3-chloromethylcyclopentane).
- This is because the elimination reaction will lead to the formation of 1-methylcyclopentane from 3-chloromethylcyclopentane.
Number of monochlorination products that can give 1-methylcyclopentane
- Among the four possible monochlorination products, only 3-chloromethylcyclopentane has the potential to give 1-methylcyclopentane upon treatment with ethanolic KOH.
- Therefore, out of the monochlorination products obtained from the free radical chlorination of methylcyclopentane, only 3 of them can give 1-methylcyclopentane as one of the products when treated with ethanolic KOH solution.
Methyl cyclopentane undergoes free radical chlorination
- When methyl cyclopentane undergoes free radical chlorination with chlorine gas in sunlight, it can form different monochlorination products due to the presence of multiple hydrogen atoms that can be replaced by chlorine.
- The possible monochlorination products include 1-chloromethylcyclopentane, 2-chloromethylcyclopentane, 3-chloromethylcyclopentane, and 4-chloromethylcyclopentane.
Treatment with ethanolic KOH solution
- When these monochlorination products are treated with ethanolic KOH solution, they undergo an elimination reaction to form alkenes.
- In order to form 1-methylcyclopentane upon treatment with ethanolic KOH, the starting monochlorination product should have the chlorine atom at the 3rd position (3-chloromethylcyclopentane).
- This is because the elimination reaction will lead to the formation of 1-methylcyclopentane from 3-chloromethylcyclopentane.
Number of monochlorination products that can give 1-methylcyclopentane
- Among the four possible monochlorination products, only 3-chloromethylcyclopentane has the potential to give 1-methylcyclopentane upon treatment with ethanolic KOH.
- Therefore, out of the monochlorination products obtained from the free radical chlorination of methylcyclopentane, only 3 of them can give 1-methylcyclopentane as one of the products when treated with ethanolic KOH solution.
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One Integer Value Correct TypeDirection (Q. Nos. 26-29) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.Methyl cyclopentane on treatment with chlorine gas in sunlight undergo free radical chlorination reaction. How many of the above monochlorination products upon treatment with ethanolic KOH solution can give 1-methyl cyclopentane as one of the product?Correct answer is '3'. Can you explain this answer?
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One Integer Value Correct TypeDirection (Q. Nos. 26-29) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.Methyl cyclopentane on treatment with chlorine gas in sunlight undergo free radical chlorination reaction. How many of the above monochlorination products upon treatment with ethanolic KOH solution can give 1-methyl cyclopentane as one of the product?Correct answer is '3'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about One Integer Value Correct TypeDirection (Q. Nos. 26-29) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.Methyl cyclopentane on treatment with chlorine gas in sunlight undergo free radical chlorination reaction. How many of the above monochlorination products upon treatment with ethanolic KOH solution can give 1-methyl cyclopentane as one of the product?Correct answer is '3'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One Integer Value Correct TypeDirection (Q. Nos. 26-29) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.Methyl cyclopentane on treatment with chlorine gas in sunlight undergo free radical chlorination reaction. How many of the above monochlorination products upon treatment with ethanolic KOH solution can give 1-methyl cyclopentane as one of the product?Correct answer is '3'. Can you explain this answer?.
One Integer Value Correct TypeDirection (Q. Nos. 26-29) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.Methyl cyclopentane on treatment with chlorine gas in sunlight undergo free radical chlorination reaction. How many of the above monochlorination products upon treatment with ethanolic KOH solution can give 1-methyl cyclopentane as one of the product?Correct answer is '3'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about One Integer Value Correct TypeDirection (Q. Nos. 26-29) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.Methyl cyclopentane on treatment with chlorine gas in sunlight undergo free radical chlorination reaction. How many of the above monochlorination products upon treatment with ethanolic KOH solution can give 1-methyl cyclopentane as one of the product?Correct answer is '3'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One Integer Value Correct TypeDirection (Q. Nos. 26-29) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.Methyl cyclopentane on treatment with chlorine gas in sunlight undergo free radical chlorination reaction. How many of the above monochlorination products upon treatment with ethanolic KOH solution can give 1-methyl cyclopentane as one of the product?Correct answer is '3'. Can you explain this answer?.
Solutions for One Integer Value Correct TypeDirection (Q. Nos. 26-29) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q.Methyl cyclopentane on treatment with chlorine gas in sunlight undergo free radical chlorination reaction. How many of the above monochlorination products upon treatment with ethanolic KOH solution can give 1-methyl cyclopentane as one of the product?Correct answer is '3'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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