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The capacity of a parallel plate condenser is 10μF when the distance between its plates is 8cm. If the distance between the plates is reducedto 4 cm then the capacity of this parallel platecondenser will be [2001]
- a)5 μF
- b)10 μF
- c)20 μF
- d)40 μF
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
The capacity of a parallel plate condenser is 10μF when the distanc...
C = 10 μF d = 8 cm
C ' = ? d ' = 4 cm
C ' = ? d ' = 4 cm
If d is halved then C will be doubled.
Hence, C ' = 2C = 2 × 10μF = 20μF
Most Upvoted Answer
The capacity of a parallel plate condenser is 10μF when the distanc...
Given Data:
- Initial capacitance (C1) = 10 µF
- Initial distance between plates (d1) = 8 cm
- Final distance between plates (d2) = 4 cm
Formula:
- The capacitance of a parallel plate capacitor is given by the formula:
C = (ε₀ * A) / d
where,
C = capacitance
ε₀ = permittivity of free space (8.85 x 10^-12 F/m)
A = area of the plates
d = distance between the plates
Calculations:
- Initial capacitance (C1) = (ε₀ * A) / d1
- Final capacitance (C2) = (ε₀ * A) / d2
- From the above equations, we can write:
C2 = C1 * (d1 / d2)
- Substituting the given values:
C2 = 10 µF * (8 cm / 4 cm)
C2 = 10 µF * 2
C2 = 20 µF
Therefore, the capacity of the parallel plate condenser will be 20 µF when the distance between its plates is reduced to 4 cm. Hence, the correct answer is option 'C' - 20 µF.
- Initial capacitance (C1) = 10 µF
- Initial distance between plates (d1) = 8 cm
- Final distance between plates (d2) = 4 cm
Formula:
- The capacitance of a parallel plate capacitor is given by the formula:
C = (ε₀ * A) / d
where,
C = capacitance
ε₀ = permittivity of free space (8.85 x 10^-12 F/m)
A = area of the plates
d = distance between the plates
Calculations:
- Initial capacitance (C1) = (ε₀ * A) / d1
- Final capacitance (C2) = (ε₀ * A) / d2
- From the above equations, we can write:
C2 = C1 * (d1 / d2)
- Substituting the given values:
C2 = 10 µF * (8 cm / 4 cm)
C2 = 10 µF * 2
C2 = 20 µF
Therefore, the capacity of the parallel plate condenser will be 20 µF when the distance between its plates is reduced to 4 cm. Hence, the correct answer is option 'C' - 20 µF.
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Community Answer
The capacity of a parallel plate condenser is 10μF when the distanc...
Capacitor (C) = Aۥ/d
capacitor is inversely proportional to distance
If distance is reduced then capacitor will be increased
Thus if 10uf then capacitor will be increased 20uf .
capacitor is inversely proportional to distance
If distance is reduced then capacitor will be increased
Thus if 10uf then capacitor will be increased 20uf .
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The capacity of a parallel plate condenser is 10μF when the distance between its plates is 8cm. If the distance between the plates is reducedto 4 cm then the capacity of this parallel platecondenser will be [2001]a)5 μFb)10 μFc)20 μFd)40 μFCorrect answer is option 'C'. Can you explain this answer?
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The capacity of a parallel plate condenser is 10μF when the distance between its plates is 8cm. If the distance between the plates is reducedto 4 cm then the capacity of this parallel platecondenser will be [2001]a)5 μFb)10 μFc)20 μFd)40 μFCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The capacity of a parallel plate condenser is 10μF when the distance between its plates is 8cm. If the distance between the plates is reducedto 4 cm then the capacity of this parallel platecondenser will be [2001]a)5 μFb)10 μFc)20 μFd)40 μFCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The capacity of a parallel plate condenser is 10μF when the distance between its plates is 8cm. If the distance between the plates is reducedto 4 cm then the capacity of this parallel platecondenser will be [2001]a)5 μFb)10 μFc)20 μFd)40 μFCorrect answer is option 'C'. Can you explain this answer?.
The capacity of a parallel plate condenser is 10μF when the distance between its plates is 8cm. If the distance between the plates is reducedto 4 cm then the capacity of this parallel platecondenser will be [2001]a)5 μFb)10 μFc)20 μFd)40 μFCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The capacity of a parallel plate condenser is 10μF when the distance between its plates is 8cm. If the distance between the plates is reducedto 4 cm then the capacity of this parallel platecondenser will be [2001]a)5 μFb)10 μFc)20 μFd)40 μFCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The capacity of a parallel plate condenser is 10μF when the distance between its plates is 8cm. If the distance between the plates is reducedto 4 cm then the capacity of this parallel platecondenser will be [2001]a)5 μFb)10 μFc)20 μFd)40 μFCorrect answer is option 'C'. Can you explain this answer?.
Solutions for The capacity of a parallel plate condenser is 10μF when the distance between its plates is 8cm. If the distance between the plates is reducedto 4 cm then the capacity of this parallel platecondenser will be [2001]a)5 μFb)10 μFc)20 μFd)40 μFCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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