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The capacity of a parallel plate condenser is C. Its capacity when the separation between the plates is halved will be
- a)4C
- b)2C
- c)C/2
- d)C/4
Correct answer is option 'B'. Can you explain this answer?
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The capacity of a parallel plate condenser is C. Its capacity when the...
The capacity of a parallel plate condenser is given as,
C=εA/d
When the separation between the plates is halved then the new capacity of the condenser is given as,
C′=εA/(d/2)
C′=2C
Thus, the new capacity of parallel plate condenser is 2C.
C=εA/d
When the separation between the plates is halved then the new capacity of the condenser is given as,
C′=εA/(d/2)
C′=2C
Thus, the new capacity of parallel plate condenser is 2C.
Most Upvoted Answer
The capacity of a parallel plate condenser is C. Its capacity when the...
Capacitance is inversely proportional to separation between plates
so, when the separation is halved then capacitance got doubled
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The capacity of a parallel plate condenser is C. Its capacity when the...
Explanation:
The capacity of a parallel plate capacitor is given by the formula:
C = εA/d
where C is the capacitance, ε is the permittivity of the medium between the plates, A is the area of the plates, and d is the distance between the plates.
When the separation between the plates is halved, the distance between the plates becomes d/2. Therefore, the new capacitance is given by:
C' = εA/(d/2) = 2εA/d
Comparing C and C', we see that C' is twice the value of C. Therefore, the correct option is (B) 2C.
HTML:
The capacity of a parallel plate capacitor is given by the formula:
C = εA/d
where C is the capacitance, ε is the permittivity of the medium between the plates, A is the area of the plates, and d is the distance between the plates.
When the separation between the plates is halved, the distance between the plates becomes d/2. Therefore, the new capacitance is given by:
C' = εA/(d/2) = 2εA/d
Comparing C and C', we see that C' is twice the value of C. Therefore, the correct option is (B) 2C.
HTML:
Explanation:
The capacity of a parallel plate capacitor is given by the formula:
C = εA/d
where C is the capacitance, ε is the permittivity of the medium between the plates, A is the area of the plates, and d is the distance between the plates.
When the separation between the plates is halved, the distance between the plates becomes d/2. Therefore, the new capacitance is given by:
C' = εA/(d/2) = 2εA/d
Comparing C and C', we see that C' is twice the value of C. Therefore, the correct option is (B) 2C.
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The capacity of a parallel plate condenser is C. Its capacity when the separation between the plates is halved will bea)4Cb)2Cc)C/2d)C/4Correct answer is option 'B'. Can you explain this answer?
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