Given that P+ Q+ R=0 . Two out of three vectors are equal in magnitude...
Analysis of Vector Magnitudes
- Let's assume the magnitudes of the vectors are a, b, and √2b.
- Given that P+ Q+ R=0, the vectors sum to zero, which means they form a closed triangle.
- Since two vectors are equal in magnitude, let's consider them as a and a.
- The third vector has a magnitude of √2 times that of the other two, which is √2a.
Determination of Possible Angles
- In a closed triangle formed by the vectors P, Q, and R, the sum of the angles is 180 degrees.
- Let's consider the two equal vectors as a and a, and the third vector as √2a.
- Since the sum of the angles in a triangle is 180 degrees, the angles opposite to the vectors with magnitudes a, a, and √2a must add up to 180 degrees.
- The angles opposite to the vectors with magnitudes a, a, and √2a are x, x, and 2x (assuming x is the angle between vectors of magnitude a, and 2x is the angle between vectors of magnitude √2a).
- Therefore, x + x + 2x = 180 degrees, which simplifies to 4x = 180 degrees, giving x = 45 degrees.
- So, the angles between the vectors can be 45 degrees, 45 degrees, and 90 degrees, which is equivalent to 135 degrees.
Conclusion
- The angles between the vectors can be 45 degrees, 45 degrees, and 90 degrees, which adds up to 180 degrees and satisfies the condition of P+ Q+ R=0.
To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.