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A car traveling at the 36km /hr speeds up to 72km/hr in 5 seconds. What it is acceleration if the same car stops in 20 seconds. What is the retardation
? Related: Numericals with Answers - Motion
Most Upvoted Answer
A car traveling at the 36km /hr speeds up to 72km/hr in 5 seconds. Wha...
Answer:
Acceleration:
To find acceleration (a) we can use the formula:
a = (v-u)/t
Substituting the given values we get:
a = (72-36)/5
a = 7.2 m/s²
Retardation:
To find retardation (r) we can use the formula:
r = (v-u)/t
Substituting the given values we get:
r = (0-72)/20
r = -3.6 m/s² (negative sign indicates retardation or deceleration)
Explanation:
The problem involves finding acceleration and retardation of a car. Acceleration is the rate at which velocity changes over time, while retardation is the rate at which velocity decreases over time. In the given problem, the car speeds up from 36 km/hr to 72 km/hr in 5 seconds, which means it has an acceleration of 7.2 m/s². On the other hand, when the car stops in 20 seconds, its velocity decreases from 72 km/hr to 0 km/hr, indicating a retardation of -3.6 m/s². The negative sign indicates that the car is decelerating or slowing down. These calculations are important in understanding the motion of objects and can be used to solve various physics problems.
Acceleration:
- Initial velocity (u) = 36 km/hr
- Final velocity (v) = 72 km/hr
- Time (t) = 5 seconds
To find acceleration (a) we can use the formula:
a = (v-u)/t
Substituting the given values we get:
a = (72-36)/5
a = 7.2 m/s²
Retardation:
- Initial velocity (u) = 72 km/hr
- Final velocity (v) = 0 km/hr
- Time (t) = 20 seconds
To find retardation (r) we can use the formula:
r = (v-u)/t
Substituting the given values we get:
r = (0-72)/20
r = -3.6 m/s² (negative sign indicates retardation or deceleration)
Explanation:
The problem involves finding acceleration and retardation of a car. Acceleration is the rate at which velocity changes over time, while retardation is the rate at which velocity decreases over time. In the given problem, the car speeds up from 36 km/hr to 72 km/hr in 5 seconds, which means it has an acceleration of 7.2 m/s². On the other hand, when the car stops in 20 seconds, its velocity decreases from 72 km/hr to 0 km/hr, indicating a retardation of -3.6 m/s². The negative sign indicates that the car is decelerating or slowing down. These calculations are important in understanding the motion of objects and can be used to solve various physics problems.
Community Answer
A car traveling at the 36km /hr speeds up to 72km/hr in 5 seconds. Wha...
A= v-u/t. [ 36 km/hr=10m/s and 72km/hr=20m/s].
= 10/20
=o.5m/s^2
= 10/20
=o.5m/s^2
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A car traveling at the 36km /hr speeds up to 72km/hr in 5 seconds. What it is acceleration if the same car stops in 20 seconds. What is the retardation Related: Numericals with Answers - Motion?
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A car traveling at the 36km /hr speeds up to 72km/hr in 5 seconds. What it is acceleration if the same car stops in 20 seconds. What is the retardation Related: Numericals with Answers - Motion? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A car traveling at the 36km /hr speeds up to 72km/hr in 5 seconds. What it is acceleration if the same car stops in 20 seconds. What is the retardation Related: Numericals with Answers - Motion? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car traveling at the 36km /hr speeds up to 72km/hr in 5 seconds. What it is acceleration if the same car stops in 20 seconds. What is the retardation Related: Numericals with Answers - Motion?.
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