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A solution of Fe2+ is titrated potentiometrically using Ce4+ solution.
Fe2+ → Fe3+ + e- , E0 = -0.77 V
emf of the Pt | Fe2+ , Fe3+ pair at 50% and 90% titration of Fe2+ are
- a)0.77 V , 0.826 V
- b)-0.826 V , -0.77 V
- c)-0.77 V ,-0.826 V
- d)0.00 V , 0.00 V
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A solution of Fe2+ is titrated potentiometrically using Ce4+solution.F...
Is oxidized to Fe3 by Ce4. The balanced chemical equation for the reaction is:
Fe2+ + Ce4+ → Fe3+ + Ce3+
The endpoint of the titration is reached when all the Fe2+ has been oxidized to Fe3+. This is indicated by a sudden increase in the potential of the solution. The potential of the Ce4+ solution is measured throughout the titration, and a plot of potential versus volume of Ce4+ added is used to determine the endpoint.
The standard potential of the Ce4+/Ce3+ couple is known, so the amount of Fe2+ in the original solution can be calculated from the volume and concentration of the Ce4+ solution used.
Potentiometric titration is a precise and accurate method for determining the concentration of Fe2+ in a solution. It is commonly used in analytical chemistry for the analysis of metal ions in solution.
Fe2+ + Ce4+ → Fe3+ + Ce3+
The endpoint of the titration is reached when all the Fe2+ has been oxidized to Fe3+. This is indicated by a sudden increase in the potential of the solution. The potential of the Ce4+ solution is measured throughout the titration, and a plot of potential versus volume of Ce4+ added is used to determine the endpoint.
The standard potential of the Ce4+/Ce3+ couple is known, so the amount of Fe2+ in the original solution can be calculated from the volume and concentration of the Ce4+ solution used.
Potentiometric titration is a precise and accurate method for determining the concentration of Fe2+ in a solution. It is commonly used in analytical chemistry for the analysis of metal ions in solution.
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A solution of Fe2+ is titrated potentiometrically using Ce4+solution.F...
When Fe2+ is 50% titrated
=
where Fe2+ is 90% titrated
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A solution of Fe2+ is titrated potentiometrically using Ce4+solution.Fe2+→ Fe3++ e-, E0= -0.77 Vemf of the Pt | Fe2+ , Fe3+ pair at 50% and 90% titration of Fe2+ are a)0.77 V , 0.826 Vb)-0.826 V , -0.77 Vc)-0.77 V ,-0.826 Vd)0.00 V , 0.00 VCorrect answer is option 'C'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A solution of Fe2+ is titrated potentiometrically using Ce4+solution.Fe2+→ Fe3++ e-, E0= -0.77 Vemf of the Pt | Fe2+ , Fe3+ pair at 50% and 90% titration of Fe2+ are a)0.77 V , 0.826 Vb)-0.826 V , -0.77 Vc)-0.77 V ,-0.826 Vd)0.00 V , 0.00 VCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solution of Fe2+ is titrated potentiometrically using Ce4+solution.Fe2+→ Fe3++ e-, E0= -0.77 Vemf of the Pt | Fe2+ , Fe3+ pair at 50% and 90% titration of Fe2+ are a)0.77 V , 0.826 Vb)-0.826 V , -0.77 Vc)-0.77 V ,-0.826 Vd)0.00 V , 0.00 VCorrect answer is option 'C'. Can you explain this answer?.
A solution of Fe2+ is titrated potentiometrically using Ce4+solution.Fe2+→ Fe3++ e-, E0= -0.77 Vemf of the Pt | Fe2+ , Fe3+ pair at 50% and 90% titration of Fe2+ are a)0.77 V , 0.826 Vb)-0.826 V , -0.77 Vc)-0.77 V ,-0.826 Vd)0.00 V , 0.00 VCorrect answer is option 'C'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A solution of Fe2+ is titrated potentiometrically using Ce4+solution.Fe2+→ Fe3++ e-, E0= -0.77 Vemf of the Pt | Fe2+ , Fe3+ pair at 50% and 90% titration of Fe2+ are a)0.77 V , 0.826 Vb)-0.826 V , -0.77 Vc)-0.77 V ,-0.826 Vd)0.00 V , 0.00 VCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solution of Fe2+ is titrated potentiometrically using Ce4+solution.Fe2+→ Fe3++ e-, E0= -0.77 Vemf of the Pt | Fe2+ , Fe3+ pair at 50% and 90% titration of Fe2+ are a)0.77 V , 0.826 Vb)-0.826 V , -0.77 Vc)-0.77 V ,-0.826 Vd)0.00 V , 0.00 VCorrect answer is option 'C'. Can you explain this answer?.
Solutions for A solution of Fe2+ is titrated potentiometrically using Ce4+solution.Fe2+→ Fe3++ e-, E0= -0.77 Vemf of the Pt | Fe2+ , Fe3+ pair at 50% and 90% titration of Fe2+ are a)0.77 V , 0.826 Vb)-0.826 V , -0.77 Vc)-0.77 V ,-0.826 Vd)0.00 V , 0.00 VCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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