A balloon is moving with a velocity of 5 metre per second in upward di...
Ans.
Method to solve :
When the packet falls from the balloon it has an initial velocity of 5 m/s.
The acceleration is the acceleration due to gravity which is 10m/s�
S = 98m
We will use the following equation of motion :
V� = U� + 2gs
V� = 25 + 2 � 10 � 98
V� = 1985V = 44.55 m/s
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A balloon is moving with a velocity of 5 metre per second in upward di...
Analysis:
The balloon is moving upward with a velocity of 5 m/s at t = 20 seconds, and at t = 10 seconds, a ball is left gently from the balloon. We need to find the speed of the ball at the ground.
Initial Conditions:
- Velocity of the balloon (Vb) = 5 m/s (upward)
- Time when the ball is released from the balloon (t) = 10 seconds
Calculations:
- The acceleration due to gravity (g) is approximately 9.8 m/s^2, acting downward.
- The initial velocity of the ball (Vb) when it is released from the balloon is the same as the velocity of the balloon, which is 5 m/s upward.
- The time taken for the ball to reach the ground can be calculated using the formula: t = sqrt(2h/g), where h is the height from which the ball is released.
- Substituting the values, we get t = sqrt(2*20/9.8) = 2.02 seconds.
Final Speed of the Ball at the Ground:
- The final velocity of the ball at the ground can be calculated using the formula: V = Vb + gt, where V is the final speed of the ball at the ground, Vb is the initial velocity of the ball, g is the acceleration due to gravity, and t is the time taken for the ball to reach the ground.
- Substituting the values, V = 5 + 9.8*2.02 = 24.99 m/s.
Therefore, the speed of the ball at the ground is approximately 24.99 m/s.
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