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Two equal point charges Q is equal to 2 under root 2 microcoulomb are placed at each of the two opposite corner of square and equal point charges Q at each of the other two corner what must be the value of q so that the resultant force on Q is zero?
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Two equal point charges Q is equal to 2 under root 2 microcoulomb ar...
Given Two equal point charges Q is equal to under root 2 microcoulomb are placed at each of the two opposite corners of a square and equal point charges q at each of the other two corners what must be the value of q so that the resultant force on Q is zero​
We need to know each side of square is of length a
So distance of charge Q from opposite charge is PR
= √b^2 + b^2 = √2b
Charges at Q and S should be negative if resultant force on charge placed at P and R is zero.
So forces act on charge Q at point R.
So force will be Fs = Fp cos 45 and Fq = Fp sin 45
1/4πεo x -qQ/QR^2 = 1/4πεo x QQ/PR^2 cos 45
- q/b^2 = Q/(√2 b)^2 x 1/√2
-q/b^2 = Q/2√2 b^2
q = - Q/2√2
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Two equal point charges Q is equal to 2 under root 2 microcoulomb ar...
Problem:
Two equal point charges Q are placed at two opposite corners of a square, while two equal point charges Q are placed at the other two opposite corners. The value of Q is 2√2 μC. What must be the value of q so that the resultant force on Q is zero?

Solution:

Step 1: Analyzing the Forces
To find the value of q that will result in zero net force on Q, we need to analyze the forces acting on it.

Force due to Q charges:
The two charges Q at the opposite corners will exert a repulsive force on Q. Since the charges are equal, the magnitude of this force can be calculated using Coulomb's law:

F = k * (Q1 * Q2) / r^2

Where:
- F is the force between the charges
- k is the Coulomb's constant (9 * 10^9 N m^2/C^2)
- Q1 and Q2 are the magnitudes of the charges
- r is the distance between the charges

In this case, Q1 = Q2 = Q and the distance between the charges is the length of one side of the square.

Force due to q charges:
The two charges q at the other corners will also exert a repulsive force on Q. Similarly, the magnitude of this force can be calculated using Coulomb's law:

F = k * (q1 * q2) / r^2

Where:
- F is the force between the charges
- k is the Coulomb's constant (9 * 10^9 N m^2/C^2)
- q1 and q2 are the magnitudes of the charges
- r is the distance between the charges

In this case, q1 = q2 = q and the distance between the charges is the length of one side of the square.

Step 2: Setting up the Equations
Since the forces due to the charges Q and q are equal in magnitude and opposite in direction, we can set up the following equations:

FQ = Fq

k * (Q * Q) / r^2 = k * (q * q) / r^2

Simplifying the equation:

Q^2 = q^2

Taking the square root of both sides:

Q = q

Step 3: Substituting Values and Solving
Given that Q = 2√2 μC, we can substitute this value into the equation:

2√2 μC = q

Squaring both sides:

8 μC^2 = q^2

Taking the square root of both sides:

q = 2√2 μC

Therefore, the value of q that will result in zero net force on Q is 2√2 μC.
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Two equal point charges Q is equal to 2 under root 2 microcoulomb are placed at each of the two opposite corner of square and equal point charges Q at each of the other two corner what must be the value of q so that the resultant force on Q is zero?
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