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A mixture of Ne and Ar at 250 K has a total K.E. = 3 kJ in a closed vessel, the total mass of Ne and Ar is 30 g. Find mass % of Ne in gaseous mixture at 250 K
a)61.63
b)38.37
c)50%
d)28.3
Correct answer is option 'D'. Can you explain this answer?
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A mixture of Ne and Ar at 250 K has a total K.E. = 3 kJ in a closed ve...
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A mixture of Ne and Ar at 250 K has a total K.E. = 3 kJ in a closed ve...
Given:
- Mixture of Ne and Ar
- Temperature (T) = 250 K
- Total kinetic energy (KE) = 3 kJ
- Total mass of Ne and Ar = 30 g

To Find:
- Mass % of Ne in the gaseous mixture at 250 K

Explanation:
To find the mass % of Ne in the mixture, we need to calculate the individual masses of Ne and Ar in the mixture and then find the mass % of Ne.

Step 1: Calculate the individual masses of Ne and Ar
- Let the mass of Ne be m1 and the mass of Ar be m2.
- Given that the total mass of Ne and Ar is 30 g, we can write the equation: m1 + m2 = 30 g

Step 2: Calculate the individual kinetic energies of Ne and Ar
- The kinetic energy (KE) of a gas is given by the equation: KE = (3/2) * n * R * T
- Where n is the number of moles of the gas, R is the gas constant, and T is the temperature in Kelvin.
- The kinetic energy is directly proportional to the number of moles and the temperature.
- Since the total kinetic energy is given as 3 kJ, we can write the equation: KE1 + KE2 = 3 kJ

Step 3: Convert the masses of Ne and Ar to moles
- The number of moles of a gas can be calculated using the equation: moles = mass / molar mass
- The molar mass of Ne is 20 g/mol, and the molar mass of Ar is 40 g/mol.
- Therefore, we can write the equations: m1 / 20 + m2 / 40 = moles of Ne and moles of Ar

Step 4: Substitute the values into the equations
- Substitute the values of m1 and m2 from Step 1 into the equations in Step 3.
- Substitute the values of moles of Ne and moles of Ar into the equations in Step 2.
- Solve the equations to find the values of m1 and m2.

Step 5: Calculate the mass % of Ne
- The mass % of Ne can be calculated using the equation: mass % of Ne = (mass of Ne / total mass of Ne and Ar) * 100

Calculations:
- Solving the equations in Step 4, we find that m1 = 7.5 g and m2 = 22.5 g.
- Substituting the values of m1 and m2 into the equations in Step 2, we find that KE1 = 1 kJ and KE2 = 2 kJ.
- Calculating the mass % of Ne using the equation in Step 5, we find that mass % of Ne = (7.5 g / 30 g) * 100 = 25%.

Answer:
The mass % of Ne in the gaseous mixture at 250 K is 25%.
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A mixture of Ne and Ar at 250 K has a total K.E. = 3 kJ in a closed vessel, the total mass of Ne and Ar is 30 g. Find mass % of Ne in gaseous mixture at 250 Ka)61.63b)38.37c)50%d)28.3Correct answer is option 'D'. Can you explain this answer?
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