Extra Numerical Questions for Physics Motion Chapter with Answers

The motion chapter in Physics deals with the study of motion and its various aspects, including speed, velocity, acceleration, and distance. Here are some extra numerical questions with answers to help you practice and improve your understanding of the chapter.

1. A car travels at a constant speed of 60 km/h. How long will it take to cover a distance of 240 km?

Solution:

- Distance = 240 km
- Speed = 60 km/h
- Time taken = Distance / Speed
- Time taken = 240 / 60 = 4 hours

Answer: The car will take 4 hours to cover a distance of 240 km.

2. A ball is thrown upward with a velocity of 20 m/s. How high will it go?

Solution:

- Initial velocity (u) = 20 m/s
- Final velocity (v) = 0 m/s (at maximum height)
- Acceleration (a) = -9.8 m/s2 (acceleration due to gravity)
- Height (h) =?

Using the formula: v^2 = u^2 + 2ah, we get:

- 0 = (20)^2 + 2(-9.8)h
- -400 = -19.6h
- h = 20.4 m

Answer: The ball will go up to a height of 20.4 m.

3. A car accelerates from 20 m/s to 40 m/s in 5 seconds. What is its acceleration?

Solution:

- Initial velocity (u) = 20 m/s
- Final velocity (v) = 40 m/s
- Time taken (t) = 5 s
- Acceleration (a) =?

Using the formula: a = (v-u) / t, we get:

- a = (40-20) / 5
- a = 4 m/s^2

Answer: The acceleration of the car is 4 m/s^2.

4. A train is moving at a speed of 80 km/h. How much time will it take to cover a distance of 400 meters?

Solution:

- Distance = 400 m
- Speed = 80 km/h = 80 x 1000 / 3600 m/s (converting km/h to m/s)
- Time taken = Distance / Speed
- Time taken = 400 / (80 x 1000 / 3600)
- Time taken = 11.25 seconds

Answer: The train will take 11.25 seconds to cover a distance of 400 meters.

5. A stone is thrown horizontally from the edge of a cliff with a speed of 20 m/s. How far from the base of the cliff will the stone hit the ground if the height of the cliff is 100 m?

Solution:

- Initial velocity (u) = 20 m/s
- Final velocity (v) = ?
- Acceleration (a) = 9.8 m/s^2 (acceleration due to gravity)
- Height (h) = 100 m
- Distance (d) =?

Using the formula: h = ut + 1/2 at^2, we get:

- 100 = 0 x t + 1/2 x 9.8 x t^2
- 100 =

OK I can send you