A car moving at 160 km per hour when crosses the marker 0 driver appli...
Analysis:
- Initial speed of the car = 160 km/h
- Final speed of the car = 40 km/h
- Distance between markers = 2 km
Calculating acceleration:
- Using the formula of uniform acceleration: \( v^2 = u^2 + 2as \) where v is final velocity, u is initial velocity, a is acceleration, and s is distance.
- Plugging in the values: \( 40^2 = 160^2 + 2a(2) \)
- Solving for a, we get: \( a = -60 \, \text{km/h}^2 \)
Calculating time taken to reach marker 2:
- Using the formula of uniform acceleration: \( v = u + at \) where t is time taken.
- Plugging in the values: \( 40 = 160 - 60t \)
- Solving for t, we get: \( t = 2 \, \text{hours} \)
Calculating the point where car's speed is 100 km/h:
- Using the formula of motion: \( v = u + at \) where v is final velocity, u is initial velocity, a is acceleration, and t is time taken.
- Plugging in the values: \( 100 = 160 - 60t \)
- Solving for t, we get: \( t = 1 \, \text{hour} \)
Conclusion:
The car would have been traveling at an instantaneous speed of 100 km/h at the midpoint between marker 0 and marker 2, which is at a distance of 1 km from marker 0.