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The ph of the solution produced by mixing equal volumeb2×10^-3 M hclo4 and 1×10^-2 M kclo4 is?
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The ph of the solution produced by mixing equal volumeb2×10^-3 M hclo4...
Solution:
Calculation of pH:
The pH of the solution can be calculated using the following steps:
Step 1: Write the balanced chemical equation for the reaction between HClO4 and KClO4.
HClO4 + KClO4 → KCl + H2ClO4
Step 2: Calculate the concentration of H2ClO4 in the solution.
Since the volumes of HClO4 and KClO4 are equal, the concentration of H2ClO4 can be calculated as follows:
[H2ClO4] = 2 × 10^-3 M
Step 3: Calculate the concentration of OH^- ions in the solution.
KClO4 is a salt of a strong base (KOH) and a weak acid (HClO4). Therefore, the solution will be slightly basic. The concentration of OH^- ions can be calculated using the following equation:
Kb = Kw/Ka
where Kb is the base dissociation constant of KClO4, Ka is the acid dissociation constant of HClO4, and Kw is the ion product constant of water.
Kb = [OH^-]^2/[KClO4]
Ka = [HClO4][OH^-]/[H2ClO4]
Kw = [H+][OH^-]
Substituting the values, we get:
[OH^-] = 1.63 × 10^-6 M
Step 4: Calculate the pH of the solution.
The pH of the solution can be calculated using the following equation:
pH = 14 - pOH
pH = 11.79
Therefore, the pH of the solution produced by mixing equal volumes of 2 × 10^-3 M HClO4 and 1 × 10^-2 M KClO4 is 11.79.
Explanation:
The pH of a solution is a measure of its acidity or basicity. It is defined as the negative logarithm of the hydrogen ion concentration ([H+]) in the solution. The pH scale ranges from 0 to 14, with a pH of 7 being neutral, pH less than 7 being acidic, and pH greater than 7 being basic.
In this problem, we are given the concentrations of HClO4 and KClO4 and asked to calculate the pH of the solution produced by mixing them. The solution will contain both HClO4 and KClO4, which will react to form KCl and H2ClO4. The concentration of H2ClO4 can be calculated using the law of conservation of mass.
Since KClO4 is a salt of a strong base and a weak acid, it will undergo hydrolysis in water to produce OH^- ions, making the solution slightly basic. The concentration of OH^- ions can be calculated using the base dissociation constant of KClO4. The pH of the solution can then be calculated using the relationship between pH and pOH.
In conclusion, the pH of the solution produced by mixing equal volumes of 2 × 10^-3 M HClO4 and 1 × 10^-2 M KClO4 is 11.79.
Calculation of pH:
The pH of the solution can be calculated using the following steps:
Step 1: Write the balanced chemical equation for the reaction between HClO4 and KClO4.
HClO4 + KClO4 → KCl + H2ClO4
Step 2: Calculate the concentration of H2ClO4 in the solution.
Since the volumes of HClO4 and KClO4 are equal, the concentration of H2ClO4 can be calculated as follows:
[H2ClO4] = 2 × 10^-3 M
Step 3: Calculate the concentration of OH^- ions in the solution.
KClO4 is a salt of a strong base (KOH) and a weak acid (HClO4). Therefore, the solution will be slightly basic. The concentration of OH^- ions can be calculated using the following equation:
Kb = Kw/Ka
where Kb is the base dissociation constant of KClO4, Ka is the acid dissociation constant of HClO4, and Kw is the ion product constant of water.
Kb = [OH^-]^2/[KClO4]
Ka = [HClO4][OH^-]/[H2ClO4]
Kw = [H+][OH^-]
Substituting the values, we get:
[OH^-] = 1.63 × 10^-6 M
Step 4: Calculate the pH of the solution.
The pH of the solution can be calculated using the following equation:
pH = 14 - pOH
pH = 11.79
Therefore, the pH of the solution produced by mixing equal volumes of 2 × 10^-3 M HClO4 and 1 × 10^-2 M KClO4 is 11.79.
Explanation:
The pH of a solution is a measure of its acidity or basicity. It is defined as the negative logarithm of the hydrogen ion concentration ([H+]) in the solution. The pH scale ranges from 0 to 14, with a pH of 7 being neutral, pH less than 7 being acidic, and pH greater than 7 being basic.
In this problem, we are given the concentrations of HClO4 and KClO4 and asked to calculate the pH of the solution produced by mixing them. The solution will contain both HClO4 and KClO4, which will react to form KCl and H2ClO4. The concentration of H2ClO4 can be calculated using the law of conservation of mass.
Since KClO4 is a salt of a strong base and a weak acid, it will undergo hydrolysis in water to produce OH^- ions, making the solution slightly basic. The concentration of OH^- ions can be calculated using the base dissociation constant of KClO4. The pH of the solution can then be calculated using the relationship between pH and pOH.
In conclusion, the pH of the solution produced by mixing equal volumes of 2 × 10^-3 M HClO4 and 1 × 10^-2 M KClO4 is 11.79.
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The ph of the solution produced by mixing equal volumeb2×10^-3 M hclo4...
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The ph of the solution produced by mixing equal volumeb2×10^-3 M hclo4 and 1×10^-2 M kclo4 is? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about The ph of the solution produced by mixing equal volumeb2×10^-3 M hclo4 and 1×10^-2 M kclo4 is? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The ph of the solution produced by mixing equal volumeb2×10^-3 M hclo4 and 1×10^-2 M kclo4 is?.
The ph of the solution produced by mixing equal volumeb2×10^-3 M hclo4 and 1×10^-2 M kclo4 is? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about The ph of the solution produced by mixing equal volumeb2×10^-3 M hclo4 and 1×10^-2 M kclo4 is? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The ph of the solution produced by mixing equal volumeb2×10^-3 M hclo4 and 1×10^-2 M kclo4 is?.
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