An aeroplane is flying with velocity 50√2 kilometre per hour in north ...
**Resultant Displacement of the Aeroplane in 2 hours**
To find the resultant displacement of the aeroplane, we need to consider both the velocity of the plane and the wind speed.
Given data:
- Velocity of the plane = 50√2 km/h (north-east direction)
- Wind speed = 25 km/h (north to south)
To find the resultant displacement, we can break down the velocity of the plane into its components in the north and east directions.
Let's assume:
- Velocity of the plane in the north direction = V_n km/h
- Velocity of the plane in the east direction = V_e km/h
**Finding the Components of Plane's Velocity:**
Using trigonometry, we can find the values of V_n and V_e.
Given:
- Velocity of the plane = 50√2 km/h
- Angle between the velocity vector and the north direction = 45 degrees (since it is flying in the north-east direction)
Using the sine and cosine functions, we can find the components of the velocity:
- V_n = velocity of the plane * sin(angle)
= 50√2 * sin(45)
= 50 km/h
- V_e = velocity of the plane * cos(angle)
= 50√2 * cos(45)
= 50 km/h
So, the velocity of the plane can be broken down into V_n = 50 km/h (north) and V_e = 50 km/h (east).
**Effect of Wind on Plane's Velocity:**
The wind is blowing at a speed of 25 km/h from north to south. This means it will affect the plane's velocity in the north and east directions.
- In the north direction, the wind is blowing against the plane's velocity, so it will reduce the component of V_n by 25 km/h. Therefore, the new V_n component becomes V_n' = V_n - wind speed = 50 - 25 = 25 km/h (north).
- In the east direction, the wind is perpendicular to the plane's velocity, so it will not affect the component V_e. Therefore, the V_e component remains the same at 50 km/h (east).
**Calculating the Resultant Displacement:**
To find the resultant displacement, we need to calculate the total distance covered by the plane in 2 hours.
- Distance covered in the north direction = V_n' * time
= 25 km/h * 2 hours
= 50 km
- Distance covered in the east direction = V_e * time
= 50 km/h * 2 hours
= 100 km
Using the Pythagorean theorem, the resultant displacement can be calculated as:
Resultant displacement = √(Distance north)^2 + (Distance east)^2
= √(50 km)^2 + (100 km)^2
= √(2500 km^2 + 10000 km^2)
= √12500 km^2
= 111.8 km
Therefore, the resultant displacement of the aeroplane after 2 hours is approximately 111.8 km.
An aeroplane is flying with velocity 50√2 kilometre per hour in north ...
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