An aeroplane is flying with velocity 50 route to kilometre per hour in...
Given Information:
An aeroplane is flying with a velocity of 50 km/h in the north-east direction. The wind is blowing at a velocity of 25 km/h from the south.
Calculating the Resultant Velocity:
To calculate the resultant velocity, we need to consider the velocities of the aeroplane and the wind separately. Since the aeroplane is flying in the north-east direction, we can break down its velocity into two components - one in the north direction and the other in the east direction.
Let's assume the northward component of the aeroplane's velocity is Vn and the eastward component is Ve.
Using the given information, we can determine the values of Vn and Ve:
- Vn = velocity of the aeroplane = 50 km/h
- Ve = velocity of the aeroplane = 50 km/h
The wind is blowing from the south, which means its velocity is in the opposite direction. Hence, the wind's velocity can be considered as:
- Wind velocity = -25 km/h (negative sign indicates the opposite direction)
To calculate the resultant velocity, we can use vector addition. The resultant velocity (Vr) can be found using the Pythagorean theorem:
Vr = √(Vn^2 + Ve^2)
Calculating the Resultant Displacement:
To calculate the resultant displacement, we need to consider the time taken by the aeroplane. In this case, the time is given as 2 hours.
The resultant displacement (Dr) can be calculated using the formula:
Dr = Vr * t
where Vr is the resultant velocity and t is the time taken.
Substituting the Values:
Let's substitute the given values into the formulas to calculate the resultant velocity and displacement.
- Vr = √(50^2 + 50^2) = √(2500 + 2500) = √(5000) = 70.71 km/h (approximately)
- Dr = Vr * t = 70.71 km/h * 2 hours = 141.42 km (approximately)
Result:
The resultant displacement of the aeroplane in 2 hours is approximately 141.42 km in the north-east direction.