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1 mol of iron reacts completely with 0.65 mol of o2 to give a mixture of only feo and fe2o3 moke ratio of ferrous oxide and ferric oxide is?
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1 mol of iron reacts completely with 0.65 mol of o2 to give a mixture ...

Calculation of Ratio of FeO to Fe2O3:

- Given: 1 mol of iron reacts completely with 0.65 mol of O2.
- The balanced chemical equation for the reaction of iron with oxygen is:
4Fe + 3O2 → 2Fe2O3.
- From the equation, we can see that 4 moles of iron react with 3 moles of O2 to form 2 moles of Fe2O3. This means that the ratio of iron to oxygen in Fe2O3 is 4:3.

Calculating the Moles of FeO and Fe2O3:

- Since 1 mol of iron reacts with 0.65 mol of O2, we can determine the limiting reactant.
- The molar ratio of Fe to O2 in the reaction is 4:3, so the number of moles of O2 required to react with 1 mol of Fe is (3/4) x 0.65 = 0.4875 mol.
- Since only 0.65 mol of O2 is available, Fe is the limiting reactant.

Calculating the Moles of FeO and Fe2O3 Formed:

- The amount of Fe2O3 formed will be half of the amount of Fe consumed, which is 0.5 mol.
- The remaining iron will react with O2 to form FeO. The total moles of iron used in the reaction are 1 mol.
- Therefore, the moles of FeO formed will be 1 - 0.5 = 0.5 mol.

Ratio of FeO to Fe2O3:

- The ratio of FeO to Fe2O3 is 0.5:0.5, which simplifies to 1:1.
- Therefore, the mole ratio of ferrous oxide (FeO) to ferric oxide (Fe2O3) in the mixture is 1:1.
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1 mol of iron reacts completely with 0.65 mol of o2 to give a mixture of only feo and fe2o3 moke ratio of ferrous oxide and ferric oxide is?
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