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1-Phenylethanol can be prepared by the reaction of benzaldehyde with
- a)Methyl bromide
- b)Ethyl iodide and magnesium
- c)Methyl iodide and magnesium
- d)Methyl bromide and aluminium bromide
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
1-Phenylethanol can be prepared by the reaction of benzaldehyde witha)...
You need to add a CH3 group to the benzaldehyde molecule. So, firstly we fix methyl group containing compound. Next step is the addition of CH3 group to the carbon of the CHO group. This can be brought about by use of grignard reagent. Therefore, C is the correct answer.
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1-Phenylethanol can be prepared by the reaction of benzaldehyde witha)...
Preparation of 1-Phenylethanol
To prepare 1-Phenylethanol, the reaction of benzaldehyde with methyl iodide and magnesium is used. This reaction is known as the Grignard reaction.
Grignard Reaction
The Grignard reaction is a powerful tool in organic synthesis that involves the formation of a carbon-carbon bond. It was discovered by French chemist Victor Grignard in the early 20th century and has since become an essential reaction in organic chemistry.
The reaction involves the reaction of an alkyl or aryl halide with magnesium metal to form a Grignard reagent. This reagent then reacts with a carbonyl compound, such as an aldehyde or ketone, to form a new carbon-carbon bond.
Reaction Mechanism
1. Formation of Grignard reagent:
- In this case, benzaldehyde reacts with methyl iodide and magnesium to form the Grignard reagent, which is methyl magnesium iodide (CH3MgI).
- This reaction occurs in an ether solvent, such as diethyl ether, to provide a suitable environment for the reaction.
2. Addition to carbonyl group:
- The Grignard reagent (CH3MgI) then reacts with benzaldehyde.
- The carbon atom of the carbonyl group in benzaldehyde is attacked by the nucleophilic carbon of the Grignard reagent.
- This leads to the formation of a new carbon-carbon bond and the substitution of the iodide group with the phenyl group from benzaldehyde.
- The product formed is 1-Phenylethanol.
Reason for choosing Methyl Iodide and Magnesium
Methyl iodide (CH3I) is chosen as the alkyl halide because it readily reacts with magnesium metal to form the Grignard reagent. It is a suitable choice due to its reactivity and availability.
Magnesium (Mg) is chosen as the metal because it readily reacts with alkyl or aryl halides to form the Grignard reagent. It acts as a nucleophile and adds to the carbon atom of the halide, leading to the formation of the Grignard reagent.
Summary
To summarize, 1-Phenylethanol can be prepared by the reaction of benzaldehyde with methyl iodide and magnesium. This reaction is known as the Grignard reaction and involves the formation of a carbon-carbon bond. Methyl iodide is chosen as the alkyl halide, and magnesium is chosen as the metal due to their reactivity and availability. The reaction proceeds in an ether solvent to provide a suitable environment for the reaction.
To prepare 1-Phenylethanol, the reaction of benzaldehyde with methyl iodide and magnesium is used. This reaction is known as the Grignard reaction.
Grignard Reaction
The Grignard reaction is a powerful tool in organic synthesis that involves the formation of a carbon-carbon bond. It was discovered by French chemist Victor Grignard in the early 20th century and has since become an essential reaction in organic chemistry.
The reaction involves the reaction of an alkyl or aryl halide with magnesium metal to form a Grignard reagent. This reagent then reacts with a carbonyl compound, such as an aldehyde or ketone, to form a new carbon-carbon bond.
Reaction Mechanism
1. Formation of Grignard reagent:
- In this case, benzaldehyde reacts with methyl iodide and magnesium to form the Grignard reagent, which is methyl magnesium iodide (CH3MgI).
- This reaction occurs in an ether solvent, such as diethyl ether, to provide a suitable environment for the reaction.
2. Addition to carbonyl group:
- The Grignard reagent (CH3MgI) then reacts with benzaldehyde.
- The carbon atom of the carbonyl group in benzaldehyde is attacked by the nucleophilic carbon of the Grignard reagent.
- This leads to the formation of a new carbon-carbon bond and the substitution of the iodide group with the phenyl group from benzaldehyde.
- The product formed is 1-Phenylethanol.
Reason for choosing Methyl Iodide and Magnesium
Methyl iodide (CH3I) is chosen as the alkyl halide because it readily reacts with magnesium metal to form the Grignard reagent. It is a suitable choice due to its reactivity and availability.
Magnesium (Mg) is chosen as the metal because it readily reacts with alkyl or aryl halides to form the Grignard reagent. It acts as a nucleophile and adds to the carbon atom of the halide, leading to the formation of the Grignard reagent.
Summary
To summarize, 1-Phenylethanol can be prepared by the reaction of benzaldehyde with methyl iodide and magnesium. This reaction is known as the Grignard reaction and involves the formation of a carbon-carbon bond. Methyl iodide is chosen as the alkyl halide, and magnesium is chosen as the metal due to their reactivity and availability. The reaction proceeds in an ether solvent to provide a suitable environment for the reaction.
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1-Phenylethanol can be prepared by the reaction of benzaldehyde witha) Methyl bromide b) Ethyl iodide and magnesium c) Methyl iodide and magnesium d) Methyl bromide and aluminium bromide Correct answer is option 'C'. Can you explain this answer?
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1-Phenylethanol can be prepared by the reaction of benzaldehyde witha) Methyl bromide b) Ethyl iodide and magnesium c) Methyl iodide and magnesium d) Methyl bromide and aluminium bromide Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 1-Phenylethanol can be prepared by the reaction of benzaldehyde witha) Methyl bromide b) Ethyl iodide and magnesium c) Methyl iodide and magnesium d) Methyl bromide and aluminium bromide Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 1-Phenylethanol can be prepared by the reaction of benzaldehyde witha) Methyl bromide b) Ethyl iodide and magnesium c) Methyl iodide and magnesium d) Methyl bromide and aluminium bromide Correct answer is option 'C'. Can you explain this answer?.
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