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One ticket is selected at random from 50 tickets numbered 00,01,02,03…..49.then the probability that the sum of digits on the selected ticket is 8,given that the product of these digits is zero,equals

  • a)
    1\50

  • b)
    1\7

  • c)
    5\14

  • d)
    1\14

Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
One ticket is selected at random from 50 tickets numbered 00,01,02,03&...
Solution
 
set A= {8,17,26,35,44}{8,17,26,35,44}
set B= {00,01,.......09,10,20,30,40}{00,01,.......09,10,20,30,40}
P(A/B)=P(A∩B)/P(B)
=1/50/14/50
=1/14
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Community Answer
One ticket is selected at random from 50 tickets numbered 00,01,02,03&...
08 can satisfy those conditions among those numbers so probability must be 1/50
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One ticket is selected at random from 50 tickets numbered 00,01,02,03…..49.then the probability that the sum of digits on the selected ticket is 8,given that the product of these digits is zero,equalsa)1\50b)1\7c)5\14d)1\14Correct answer is option 'D'. Can you explain this answer?
Question Description
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