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How many moles of magnesium phosphate, Mg3 (PO4)2 will contain 0.25 mole of oxygen atoms?
  • a)
    3.125 × 10-2
  • b)
    1.25 × 10-2
  • c)
    2.5 × 10-2
  • d)
    0.02
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
How many moles of magnesium phosphate, Mg3 (PO4)2 will contain 0.25 mo...
Mg3(P04)→ 3Mg
→2 P
→ 8 mole oxygen
8 mole of oxygen - 1 mole Mg3 (P0)2
0.25 - ? 0.25/8 = 3 x 10-2
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Most Upvoted Answer
How many moles of magnesium phosphate, Mg3 (PO4)2 will contain 0.25 mo...
To solve this problem, we need to first determine how many oxygen atoms are present in one mole of Mg3(PO4)2.

In Mg3(PO4)2, there are 8 oxygen atoms per molecule (2 from each PO4 group). Therefore, one mole of Mg3(PO4)2 contains 8 moles of oxygen atoms.

To find out how many moles of Mg3(PO4)2 contain 0.25 mole of oxygen atoms, we can set up a proportion:

1 mole Mg3(PO4)2 / 8 moles oxygen = x moles Mg3(PO4)2 / 0.25 moles oxygen

Solving for x, we get:

x = (0.25 moles oxygen x 1 mole Mg3(PO4)2) / 8 moles oxygen

x = 0.03125 moles Mg3(PO4)2

Therefore, the answer is 0.03125 moles Mg3(PO4)2, which is equivalent to 3.125 x 10^-2 moles Mg3(PO4)2 or 3.125 moles Mg3(PO4)2 rounded to three significant figures.
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Community Answer
How many moles of magnesium phosphate, Mg3 (PO4)2 will contain 0.25 mo...
One mole of magnesium phosphate contains 8 moles of Oxygen atoms. Then multiplying (0.25*1/8) to 1 mole of magnesium phosphate gives you 3.125*10^-2 moles of magnesium phosphate
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