A sample of Ba3(PO4) 2 contain 0.6 moles of O atoms. The no. Of moles of P atoms in the sample is?

Question

Answer

Given information:

Sample contains Ba3(PO4)2

0.6 moles of O atoms present

Finding:

To calculate the no. of moles of P atoms in the sample

Solution:

First, we need to find the no. of moles of O atoms in Ba3(PO4)2

Since there are 2 PO4 groups in Ba3(PO4)2, the total moles of O atoms in one Ba3(PO4)2 molecule is:

O atoms = 2 x 4 = 8 moles

Therefore, in the given sample:

0.6 moles of O atoms = 0.6/8 = 0.075 moles of Ba3(PO4)2

Next, we need to find the no. of moles of P atoms in 0.075 moles of Ba3(PO4)2

One Ba3(PO4)2 molecule contains 2 P atoms

Therefore, 0.075 moles of Ba3(PO4)2 will contain:

2 x 0.075 = 0.15 moles of P atoms

Answer:

The no. of moles of P atoms in the sample is 0.15 moles

Answer

8=0.6
so for 2 atom no.if mole =.6*2/8=.15