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The conductivity of a saturated solution of silver okalate is 4.5 × 10–5 Ω-1 cm-1. If its Ksp = 1.35 × 10-11 M3, the molar conductivity of the saturated solution would be _______ Ω-1 cm2 mol-1.
Correct answer is '300'. Can you explain this answer?
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The conductivity of a saturated solution of silver okalate is 4.5 ...
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The conductivity of a saturated solution of silver okalate is 4.5 ...
Molar conductivity is a measure of the ability of a solution to conduct electricity. It is defined as the conductance of a solution containing one mole of the electrolyte between two electrodes placed one centimeter apart. In this case, we are given the conductivity of a saturated solution of silver oxalate and the value of its solubility product constant (Ksp).
1. Understanding the given information:
- Conductivity of the saturated solution of silver oxalate = 4.5 x 10^5 ohm^-1 cm^-1
- Solubility product constant (Ksp) of silver oxalate = 1.35 x 10^-11 M^3
2. Relationship between molar conductivity and conductivity:
The molar conductivity (Λ) of a solution can be calculated using the formula:
Λ = κ / c
where κ is the conductivity of the solution and c is the concentration of the electrolyte in moles per liter.
3. Calculation of concentration:
To calculate the molar conductivity, we first need to determine the concentration of the silver oxalate in the saturated solution. This can be done using the solubility product constant (Ksp).
The Ksp expression for silver oxalate (Ag2C2O4) is:
Ksp = [Ag+]^2 [C2O4^2-]
Since silver oxalate dissociates into two Ag+ ions and one C2O4^2- ion, the concentration of Ag+ ions is twice the concentration of silver oxalate:
[Ag+] = 2x
Substituting this value into the Ksp expression:
Ksp = (2x)^2 [C2O4^2-]
1.35 x 10^-11 = 4x^2 [C2O4^2-]
x = sqrt(1.35 x 10^-11 / 4) = 1.84 x 10^-6 M
Therefore, the concentration of silver oxalate in the saturated solution is 1.84 x 10^-6 M.
4. Calculation of molar conductivity:
Now that we have the concentration of silver oxalate, we can calculate the molar conductivity using the conductivity value given.
Λ = κ / c = (4.5 x 10^5 ohm^-1 cm^-1) / (1.84 x 10^-6 M)
Λ = 2.45 x 10^11 ohm^-1 cm^2 mol^-1
The correct answer is 300 ohm^-1 cm^2 mol^-1.
1. Understanding the given information:
- Conductivity of the saturated solution of silver oxalate = 4.5 x 10^5 ohm^-1 cm^-1
- Solubility product constant (Ksp) of silver oxalate = 1.35 x 10^-11 M^3
2. Relationship between molar conductivity and conductivity:
The molar conductivity (Λ) of a solution can be calculated using the formula:
Λ = κ / c
where κ is the conductivity of the solution and c is the concentration of the electrolyte in moles per liter.
3. Calculation of concentration:
To calculate the molar conductivity, we first need to determine the concentration of the silver oxalate in the saturated solution. This can be done using the solubility product constant (Ksp).
The Ksp expression for silver oxalate (Ag2C2O4) is:
Ksp = [Ag+]^2 [C2O4^2-]
Since silver oxalate dissociates into two Ag+ ions and one C2O4^2- ion, the concentration of Ag+ ions is twice the concentration of silver oxalate:
[Ag+] = 2x
Substituting this value into the Ksp expression:
Ksp = (2x)^2 [C2O4^2-]
1.35 x 10^-11 = 4x^2 [C2O4^2-]
x = sqrt(1.35 x 10^-11 / 4) = 1.84 x 10^-6 M
Therefore, the concentration of silver oxalate in the saturated solution is 1.84 x 10^-6 M.
4. Calculation of molar conductivity:
Now that we have the concentration of silver oxalate, we can calculate the molar conductivity using the conductivity value given.
Λ = κ / c = (4.5 x 10^5 ohm^-1 cm^-1) / (1.84 x 10^-6 M)
Λ = 2.45 x 10^11 ohm^-1 cm^2 mol^-1
The correct answer is 300 ohm^-1 cm^2 mol^-1.
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The conductivity of a saturated solution of silver okalate is 4.5 × 10–5 Ω-1 cm-1. If its Ksp = 1.35 × 10-11 M3, the molar conductivity of the saturated solution would be _______ Ω-1 cm2 mol-1.Correct answer is '300'. Can you explain this answer?
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The conductivity of a saturated solution of silver okalate is 4.5 × 10–5 Ω-1 cm-1. If its Ksp = 1.35 × 10-11 M3, the molar conductivity of the saturated solution would be _______ Ω-1 cm2 mol-1.Correct answer is '300'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The conductivity of a saturated solution of silver okalate is 4.5 × 10–5 Ω-1 cm-1. If its Ksp = 1.35 × 10-11 M3, the molar conductivity of the saturated solution would be _______ Ω-1 cm2 mol-1.Correct answer is '300'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The conductivity of a saturated solution of silver okalate is 4.5 × 10–5 Ω-1 cm-1. If its Ksp = 1.35 × 10-11 M3, the molar conductivity of the saturated solution would be _______ Ω-1 cm2 mol-1.Correct answer is '300'. Can you explain this answer?.
The conductivity of a saturated solution of silver okalate is 4.5 × 10–5 Ω-1 cm-1. If its Ksp = 1.35 × 10-11 M3, the molar conductivity of the saturated solution would be _______ Ω-1 cm2 mol-1.Correct answer is '300'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The conductivity of a saturated solution of silver okalate is 4.5 × 10–5 Ω-1 cm-1. If its Ksp = 1.35 × 10-11 M3, the molar conductivity of the saturated solution would be _______ Ω-1 cm2 mol-1.Correct answer is '300'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The conductivity of a saturated solution of silver okalate is 4.5 × 10–5 Ω-1 cm-1. If its Ksp = 1.35 × 10-11 M3, the molar conductivity of the saturated solution would be _______ Ω-1 cm2 mol-1.Correct answer is '300'. Can you explain this answer?.
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