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The specific conductivity of 0.02 M KCl solution at 25°C is 2.768 × 10–3 ohm–1 cm–1. The resistance of this solution at 25°C when measured with a particular cell was 250.2 ohms. The resistance of 0.01 M CuSO4 solution at 25°C measured with the same cell was 8331 ohms. Calculate the molar conductivity (in s–1 cm2 mol–1& rounded up to three decimal places) of the copper sulfate solution:
    Correct answer is between '8.305,8.320'. Can you explain this answer?
    Verified Answer
    The specific conductivity of 0.02 M KCl solution at 25°C is 2.768 ...
    Cell constant   = (Sp.cond.of KCl)/(Conductane of KCl)
    = (2.768 x 10^-3)/(I/250.2)
     = 2.768  x 10^-3  x 250.2
     For 0.01 M CuSO3 solution
    Sp. conductivity = Cell constant  x conductance
     = 2.768 x 10^-3 x 250.2  x 1/8331
     Molar conductance = Sp. cond.  x 1000/c
    =  (2.768 x10^-3  x 25.2)/8331  x 1000/(1/100)
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    Most Upvoted Answer
    The specific conductivity of 0.02 M KCl solution at 25°C is 2.768 ...
    °C is 0.014 S/cm.

    Explanation:

    The specific conductivity (κ) is defined as the conductivity of a solution divided by the distance between the electrodes and the area of the electrodes. It is expressed in Siemens per centimeter (S/cm).

    The specific conductivity of a solution is affected by various factors such as temperature, concentration, and type of electrolyte.

    In this case, the specific conductivity of a 0.02 M KCl solution at 25°C is given as 0.014 S/cm.

    This means that if we place two electrodes 1 cm apart in the solution and apply a potential difference of 1 volt, the current that flows between the electrodes will be 0.014 amperes.

    It is important to note that the specific conductivity of a solution increases with concentration and temperature. Therefore, if the concentration of KCl is increased or the temperature is raised, the specific conductivity of the solution will also increase.
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    The specific conductivity of 0.02 M KCl solution at 25°C is 2.768 × 10–3 ohm–1 cm–1. The resistance of this solution at 25°C when measured with a particular cell was 250.2 ohms. The resistance of 0.01 M CuSO4 solution at 25°C measured with the same cell was 8331 ohms. Calculate the molar conductivity (in s–1 cm2 mol–1& rounded up to three decimal places) of the copper sulfate solution:Correct answer is between '8.305,8.320'. Can you explain this answer?
    Question Description
    The specific conductivity of 0.02 M KCl solution at 25°C is 2.768 × 10–3 ohm–1 cm–1. The resistance of this solution at 25°C when measured with a particular cell was 250.2 ohms. The resistance of 0.01 M CuSO4 solution at 25°C measured with the same cell was 8331 ohms. Calculate the molar conductivity (in s–1 cm2 mol–1& rounded up to three decimal places) of the copper sulfate solution:Correct answer is between '8.305,8.320'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The specific conductivity of 0.02 M KCl solution at 25°C is 2.768 × 10–3 ohm–1 cm–1. The resistance of this solution at 25°C when measured with a particular cell was 250.2 ohms. The resistance of 0.01 M CuSO4 solution at 25°C measured with the same cell was 8331 ohms. Calculate the molar conductivity (in s–1 cm2 mol–1& rounded up to three decimal places) of the copper sulfate solution:Correct answer is between '8.305,8.320'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The specific conductivity of 0.02 M KCl solution at 25°C is 2.768 × 10–3 ohm–1 cm–1. The resistance of this solution at 25°C when measured with a particular cell was 250.2 ohms. The resistance of 0.01 M CuSO4 solution at 25°C measured with the same cell was 8331 ohms. Calculate the molar conductivity (in s–1 cm2 mol–1& rounded up to three decimal places) of the copper sulfate solution:Correct answer is between '8.305,8.320'. Can you explain this answer?.
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