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A particular conductivity cell has a resistance of 468 Ω when filled with 0.001 M HC1, of 1 580 2 when filled with 0.001 M NaCl, and of 1 650 2 when filled with 0.001 M NaNO3. The molar conductivity of NaNO3 is 121Sc * m ^ 2 * mo * l ^ - 1 Neglecting changes in values with concentration, calculate (a) Conductivity of 0.001 M NaNO3. (b) Cell constant. (c) Resistance of the cell when filled with 0.001 M HNO3 and molar conductivity of ΗΝΟ3.?
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A particular conductivity cell has a resistance of 468 Ω when filled w...
Conductivity of 0.001 M NaNO3:
- The conductivity cell has a resistance of 1650 Ω when filled with 0.001 M NaNO3.
- The resistance of the cell when filled with 0.001 M NaCl is 1580 Ω.
- The molar conductivity of NaNO3 is given as 121 S cm^2 mol^-1.
Using the formula for conductivity (κ) = 1 / R, where R is the resistance, we can calculate the conductivity of 0.001 M NaNO3:
Conductivity of 0.001 M NaNO3 = 1 / 1650 = 0.000606 S

Cell constant:
- The cell constant can be calculated using the formula κ = Λ / C, where Λ is the molar conductivity and C is the concentration in mol/L.
- Given that the molar conductivity of NaNO3 is 121 S cm^2 mol^-1 and the concentration is 0.001 M, we can calculate the cell constant as follows:
Cell constant = 121 / 0.001 = 121000 cm^-1

Resistance of the cell when filled with 0.001 M HNO3 and molar conductivity of HNO3:
- The resistance of the cell when filled with 0.001 M HCl is 468 Ω.
- Since HNO3 is a strong electrolyte like HCl, we can assume that the molar conductivity of HNO3 is similar to that of HCl.
- Therefore, the resistance of the cell when filled with 0.001 M HNO3 would also be 468 Ω.
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A particular conductivity cell has a resistance of 468 Ω when filled w...
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A particular conductivity cell has a resistance of 468 Ω when filled with 0.001 M HC1, of 1 580 2 when filled with 0.001 M NaCl, and of 1 650 2 when filled with 0.001 M NaNO3. The molar conductivity of NaNO3 is 121Sc * m ^ 2 * mo * l ^ - 1 Neglecting changes in values with concentration, calculate (a) Conductivity of 0.001 M NaNO3. (b) Cell constant. (c) Resistance of the cell when filled with 0.001 M HNO3 and molar conductivity of ΗΝΟ3.?
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A particular conductivity cell has a resistance of 468 Ω when filled with 0.001 M HC1, of 1 580 2 when filled with 0.001 M NaCl, and of 1 650 2 when filled with 0.001 M NaNO3. The molar conductivity of NaNO3 is 121Sc * m ^ 2 * mo * l ^ - 1 Neglecting changes in values with concentration, calculate (a) Conductivity of 0.001 M NaNO3. (b) Cell constant. (c) Resistance of the cell when filled with 0.001 M HNO3 and molar conductivity of ΗΝΟ3.? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about A particular conductivity cell has a resistance of 468 Ω when filled with 0.001 M HC1, of 1 580 2 when filled with 0.001 M NaCl, and of 1 650 2 when filled with 0.001 M NaNO3. The molar conductivity of NaNO3 is 121Sc * m ^ 2 * mo * l ^ - 1 Neglecting changes in values with concentration, calculate (a) Conductivity of 0.001 M NaNO3. (b) Cell constant. (c) Resistance of the cell when filled with 0.001 M HNO3 and molar conductivity of ΗΝΟ3.? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particular conductivity cell has a resistance of 468 Ω when filled with 0.001 M HC1, of 1 580 2 when filled with 0.001 M NaCl, and of 1 650 2 when filled with 0.001 M NaNO3. The molar conductivity of NaNO3 is 121Sc * m ^ 2 * mo * l ^ - 1 Neglecting changes in values with concentration, calculate (a) Conductivity of 0.001 M NaNO3. (b) Cell constant. (c) Resistance of the cell when filled with 0.001 M HNO3 and molar conductivity of ΗΝΟ3.?.
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