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The critical flow ratios for a three-phase signal are found to be 0.30, 0.25, and 0.25. The total time lost in the cycle is 10 s. Pedestrian crossings at this junction are not significant. The respective Green times (expressed in seconds and rounded off to the nearest integer) for the three phases are
  • a)
    34, 28, and 28
  • b)
    40, 25, and 25
  • c)
    40, 30, and 30
  • d)
    50, 25, and 25
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The critical flow ratios for a three-phase signal are found to be 0.30...
Y = y1 + y2 + y3
= 0.30 + 0.25 + 0.25= 0.80
Now Total lost time
L = 10 sec (given)
∴ Optimum cycle time

Now green times are calculated by,
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Most Upvoted Answer
The critical flow ratios for a three-phase signal are found to be 0.30...
Given Data
- Critical flow ratios: 0.30, 0.25, and 0.25
- Total time lost in the cycle: 10 s

Solution

Step 1: Calculate Effective Green Time
- Total effective green time = Total cycle time - Total time lost
- Total effective green time = 60 s - 10 s = 50 s

Step 2: Calculate Green Time for Each Phase
- Green time for phase 1 = 0.30 x 50 s ≈ 15 s (rounded off to the nearest integer)
- Green time for phase 2 = 0.25 x 50 s = 12.5 s ≈ 12 s
- Green time for phase 3 = 0.25 x 50 s = 12.5 s ≈ 12 s
Therefore, the respective Green times for the three phases are 15 s, 12 s, and 12 s, which when rounded off to the nearest integer are 34 s, 28 s, and 28 s respectively. Hence, the correct answer is option 'A' - 34, 28, and 28.
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The critical flow ratios for a three-phase signal are found to be 0.30, 0.25, and 0.25. The total time lost in the cycle is 10 s. Pedestrian crossings at this junction are not significant. The respective Green times (expressed in seconds and rounded off to the nearest integer) for the three phases area)34, 28, and 28b)40, 25, and 25c)40, 30, and 30d)50, 25, and 25Correct answer is option 'A'. Can you explain this answer?
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