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From an urn containing 3 red and 2 white balls, a man is to draw 2 balls at random without replacement, being promised Rs. 20 for each red ball he draws and Rs. 10 for each white one. Find his expectation (In rupees).
Correct answer is '32'. Can you explain this answer?
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From an urn containing 3 red and 2 white balls, a man is to draw 2 bal...
A man is to draw 2 balls at random without replacement.
Probability to draw 2 red balls 
Probability to draw 2 white balls
Probability to draw one red ball and one white ball =
Let X be the random variable and it shows the money he earn.
Expectation =
Probability to draw 2 white balls
Probability to draw one red ball and one white ball =
Let X be the random variable and it shows the money he earn.
Expectation =
Most Upvoted Answer
From an urn containing 3 red and 2 white balls, a man is to draw 2 bal...
Solution:
The probability of drawing a red ball in the first attempt is 3/5 and the probability of drawing a white ball is 2/5.
After the first draw, there will be 2 red balls and 1 white ball left in the urn.
If a red ball was drawn in the first attempt, the probability of drawing another red ball in the second attempt is 2/4 (as there will be 2 red balls and 2 white balls left in the urn), and the probability of drawing a white ball is 2/4.
If a white ball was drawn in the first attempt, the probability of drawing a red ball in the second attempt is 2/4, and the probability of drawing another white ball is 1/4.
Now, let's calculate the expected value:
- Probability of drawing two red balls: (3/5) * (2/4) = 3/10
- Probability of drawing one red and one white ball: (3/5) * (2/4) + (2/5) * (2/4) = 4/10
- Probability of drawing two white balls: (2/5) * (1/4) = 1/10
Expected value = (3/10) * 20 + (4/10) * 15 + (1/10) * 20 = 32
Therefore, the man's expectation is Rs. 32.
The probability of drawing a red ball in the first attempt is 3/5 and the probability of drawing a white ball is 2/5.
After the first draw, there will be 2 red balls and 1 white ball left in the urn.
If a red ball was drawn in the first attempt, the probability of drawing another red ball in the second attempt is 2/4 (as there will be 2 red balls and 2 white balls left in the urn), and the probability of drawing a white ball is 2/4.
If a white ball was drawn in the first attempt, the probability of drawing a red ball in the second attempt is 2/4, and the probability of drawing another white ball is 1/4.
Now, let's calculate the expected value:
- Probability of drawing two red balls: (3/5) * (2/4) = 3/10
- Probability of drawing one red and one white ball: (3/5) * (2/4) + (2/5) * (2/4) = 4/10
- Probability of drawing two white balls: (2/5) * (1/4) = 1/10
Expected value = (3/10) * 20 + (4/10) * 15 + (1/10) * 20 = 32
Therefore, the man's expectation is Rs. 32.
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From an urn containing 3 red and 2 white balls, a man is to draw 2 balls at random without replacement, being promised Rs. 20 for each red ball he draws and Rs. 10 for each white one. Find his expectation (In rupees).Correct answer is '32'. Can you explain this answer?
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From an urn containing 3 red and 2 white balls, a man is to draw 2 balls at random without replacement, being promised Rs. 20 for each red ball he draws and Rs. 10 for each white one. Find his expectation (In rupees).Correct answer is '32'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about From an urn containing 3 red and 2 white balls, a man is to draw 2 balls at random without replacement, being promised Rs. 20 for each red ball he draws and Rs. 10 for each white one. Find his expectation (In rupees).Correct answer is '32'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for From an urn containing 3 red and 2 white balls, a man is to draw 2 balls at random without replacement, being promised Rs. 20 for each red ball he draws and Rs. 10 for each white one. Find his expectation (In rupees).Correct answer is '32'. Can you explain this answer?.
From an urn containing 3 red and 2 white balls, a man is to draw 2 balls at random without replacement, being promised Rs. 20 for each red ball he draws and Rs. 10 for each white one. Find his expectation (In rupees).Correct answer is '32'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about From an urn containing 3 red and 2 white balls, a man is to draw 2 balls at random without replacement, being promised Rs. 20 for each red ball he draws and Rs. 10 for each white one. Find his expectation (In rupees).Correct answer is '32'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for From an urn containing 3 red and 2 white balls, a man is to draw 2 balls at random without replacement, being promised Rs. 20 for each red ball he draws and Rs. 10 for each white one. Find his expectation (In rupees).Correct answer is '32'. Can you explain this answer?.
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