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In slider -crank mechanism, the crank is rotating with an angular velocity of 10 rad /s in counter clock wise direction. At the instant when the crank makes an angle of 60° with the direction of the piston movement, the velocity of the piston is 2 m/s. What will be the radius of the crank if the length of the connecting rod is four times of the radius of the crank.
  • a)
    12 cm
  • b)
    25 cm
  • c)
    20.5 cm
  • d)
    18.4 cm
Correct answer is option 'C'. Can you explain this answer?
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In slider -crank mechanism, the crank is rotating with an angular velo...

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In slider -crank mechanism, the crank is rotating with an angular velo...
Degrees with the horizontal, the slider has a velocity of 5 m/s in the upward direction. The length of the crank is 0.5 m and the length of the connecting rod is 1.5 m. Find:

a) The angular velocity of the connecting rod

b) The velocity and acceleration of the slider when the crank makes an angle of 60 degrees with the horizontal.

c) The position of the slider when the crank makes an angle of 60 degrees with the horizontal.

Solution:

a) The angular velocity of the connecting rod can be found using the velocity diagram of the slider-crank mechanism. The velocity diagram is shown below:

From the velocity diagram, we can write:

v_a = v_b + v_c

where v_a is the velocity of the slider, v_b is the velocity of the crank pin and v_c is the velocity of the connecting rod.

We know that v_a = 5 m/s and v_b = rω, where r is the length of the crank and ω is the angular velocity of the crank. Substituting the values, we get:

5 = 0.5 × 10 + v_c

v_c = 0 m/s

Now, we can find the angular velocity of the connecting rod using the following equation:

ω_c = ω - arccos((r^2 + L^2 - d^2) / 2rL)

where L is the length of the connecting rod and d is the distance between the crank pin and slider. Substituting the values, we get:

ω_c = 10 - arccos((0.5^2 + 1.5^2 - 2(0.5)(1.5)cos60) / (2 × 0.5 × 1.5))

ω_c = 3.24 rad/s

Therefore, the angular velocity of the connecting rod is 3.24 rad/s.

b) To find the velocity and acceleration of the slider, we can use the velocity and acceleration diagrams. The velocity diagram is already shown above. The acceleration diagram is shown below:

From the acceleration diagram, we can write:

a_a = a_b + a_c + a_t

where a_a is the acceleration of the slider, a_b is the acceleration of the crank pin, a_c is the acceleration of the connecting rod and a_t is the tangential acceleration of the slider.

We know that a_b = rα, where α is the angular acceleration of the crank. Substituting the values, we get:

a_b = 0.5 × α

Now, we can find the angular acceleration of the crank using the following equation:

α = -ω^2 / r

Substituting the values, we get:

α = -400 rad/s^2

Therefore, a_b = -200 m/s^2

We also know that a_c = L(α_c - α_b), where α_c is the angular acceleration of the connecting rod. From the velocity diagram, we know that v_c = Lω_c. Differentiating with respect to time, we get:

a_c = Lα_c

Substituting the values, we get:

a_c = 1.5(α_c - α_b)

Now, we can write:

a_a = a_b + a_c + a_t

Substituting the values, we get:

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In slider -crank mechanism, the crank is rotating with an angular velocity of 10 rad /s in counter clock wise direction. At the instant when the crank makes an angle of 60° with the direction of the piston movement, the velocity of the piston is 2 m/s. What will be the radius of the crank if the length of the connecting rod is four times of the radius of the crank.a)12 cmb)25 cmc)20.5 cmd)18.4 cmCorrect answer is option 'C'. Can you explain this answer?
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