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In an examination, 20% of the students have failed in Computer Networks, 30% of the students have failed in Computer Architecture and 10% in Computer Networks and Computer Architecture. If a student is selected at random, then what is the probability that the student has failed in at least one subject?
- a)1/5
- b)2/5
- c)3/5
- d)4/5
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
In an examination, 20% of the students have failed in Computer Network...
Let the number of students be 100.
P(N)→ probability that students failed in Computer Networks
P(A)→ probability that students failed in Computer Architecture
P(N∩A)→ probability that the student has failed in both the subject
P(A)→ probability that students failed in Computer Architecture
P(N∩A)→ probability that the student has failed in both the subject
P(NUA)→ probability that the student has failed in atleast one subject
P(NUA) = P(N) + P(A) − P(N∩A)
Most Upvoted Answer
In an examination, 20% of the students have failed in Computer Network...
Question Analysis:
We are given that 20% of the students have failed in Computer Networks, 30% of the students have failed in Computer Architecture, and 10% of the students have failed in both subjects. We need to find the probability that a student has failed in at least one subject.
Probability of Failing in Computer Networks:
Given that 20% of the students have failed in Computer Networks, we can say that the probability of failing in Computer Networks is 0.20.
Probability of Failing in Computer Architecture:
Given that 30% of the students have failed in Computer Architecture, we can say that the probability of failing in Computer Architecture is 0.30.
Probability of Failing in Both Subjects:
Given that 10% of the students have failed in both Computer Networks and Computer Architecture, we can say that the probability of failing in both subjects is 0.10.
Probability of Failing in at Least One Subject:
To find the probability of failing in at least one subject, we need to subtract the probability of passing both subjects from 1. This can be calculated using the formula:
P(A or B) = P(A) + P(B) - P(A and B)
where A represents failing in Computer Networks and B represents failing in Computer Architecture.
So, the probability of failing in at least one subject is:
P(Failing in at least one subject) = P(Failing in Computer Networks) + P(Failing in Computer Architecture) - P(Failing in both subjects)
= 0.20 + 0.30 - 0.10
= 0.40
Therefore, the probability that a student has failed in at least one subject is 0.40, which is equivalent to 2/5.
Answer:
The correct answer is option B) 2/5.
We are given that 20% of the students have failed in Computer Networks, 30% of the students have failed in Computer Architecture, and 10% of the students have failed in both subjects. We need to find the probability that a student has failed in at least one subject.
Probability of Failing in Computer Networks:
Given that 20% of the students have failed in Computer Networks, we can say that the probability of failing in Computer Networks is 0.20.
Probability of Failing in Computer Architecture:
Given that 30% of the students have failed in Computer Architecture, we can say that the probability of failing in Computer Architecture is 0.30.
Probability of Failing in Both Subjects:
Given that 10% of the students have failed in both Computer Networks and Computer Architecture, we can say that the probability of failing in both subjects is 0.10.
Probability of Failing in at Least One Subject:
To find the probability of failing in at least one subject, we need to subtract the probability of passing both subjects from 1. This can be calculated using the formula:
P(A or B) = P(A) + P(B) - P(A and B)
where A represents failing in Computer Networks and B represents failing in Computer Architecture.
So, the probability of failing in at least one subject is:
P(Failing in at least one subject) = P(Failing in Computer Networks) + P(Failing in Computer Architecture) - P(Failing in both subjects)
= 0.20 + 0.30 - 0.10
= 0.40
Therefore, the probability that a student has failed in at least one subject is 0.40, which is equivalent to 2/5.
Answer:
The correct answer is option B) 2/5.
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Community Answer
In an examination, 20% of the students have failed in Computer Network...
Yes
actually
p(a)=20=20/100
p(b)=30=30÷100
p(a intersecting b)=10=10/100
then
=p(a)+p(b)-p(a intersecting b)=2/5
actually
p(a)=20=20/100
p(b)=30=30÷100
p(a intersecting b)=10=10/100
then
=p(a)+p(b)-p(a intersecting b)=2/5
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